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Naya [18.7K]
3 years ago
14

Gabriela walked to school on 16 of the 24 school days in March. Which value is equivalent to the

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

.

Step-by-step explanation:

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If 24, x, and 6 form the first three terms of an arithmetic sequence
AveGali [126]
<h3>Answer:  15</h3>

===============================================

Work Shown:

d = common difference

p = first term = 24

q = second term = a+d = 24+d

r = third term = q+d = 24+d+d = 24+2d = 6

------------

Solve for d

24+2d = 6

2d = 6-24

2d = -18

d = -18/2

d = -9

We add -9 to each term to get the next term. This is the same as subtracting 9 from each term to get the next term.

------------

First term = 24

Second term = 24-9 = 15

Third term = 15-9 = 6

We get the sequence 24, 15, 6

7 0
3 years ago
If $500 is shared in the ratio 2:3:9 then the difference between the largest and the smallest shares is
madreJ [45]

Answer:

$250

Step-by-step explanation:

Total parts:

2+3+9 = 14

500/14 = 250/7

2×250/7 : 3×250/7 : 9×250/7

500/7 : 750/7 : 2250/7

The largest share is 2250/7, the smallest share is 500/7.

Find the difference.

2250/7 - 500/7 = 250

8 0
3 years ago
Read 2 more answers
Two sides of a triangle have the same length. The third side measures 4 m less than twice the common length. The perimeter of th
velikii [3]

Answer:

the length of the two equal sides: 8m

the length of the third side: 8m-4m=4m

8m×2+4m=20m

5 0
3 years ago
If s(x) = x-7 and f(x) = 4x? – X+3, which expression is equivalent to (tos)(x)?
lesya692 [45]

Answer:

4(x-7)^2-(x-7)+3 (Assuming t is f)

Step-by-step explanation:

Let s(x)=x-7 and t(x)=4x^2-x+3 .

(t o s)(x)=t(s(x))=t(x-7)

Before I continue this means replace the orginal x in t with x-7.

This will then give you

4(x-7)^2-(x-7)+3

4 0
3 years ago
-2(x-6)+7=35<br> How do I solve this equation with all the steps
vlada-n [284]
-2(x-6)+7=35 -2x+6+7=35 (Distributive property) -2x+13=35 (Simplify, combine like terms) -2x+13-13=35-13 -2x=22 -2x/-2=22/-2 X=-11
3 0
3 years ago
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