Answer:
f(2) = -2
Step-by-step explanation:
Substitute 2 everywhere you see an x so f(2) = -2(
) - 2(2) + 10 so
f(2) = -2(4) - 4 + 10, so f(2) = -8-4+10, f(2) = -12+10, f(2) = -2
Complete question :
designs a board game in which a card is drawn on each turn. • A blue card means move forward 4 squares. • A red card means move back 6 squares. Liam suggests adding some other cards to Sia's game Part A Liam explains that drawing a yellow card is equivalent to drawing a blue card followed by a red card. How many spaces forward or backward does a player move after drawing a yellow card? Justify your answer.
Answer:
2 squares backward
Step-by-step explanation:
Given the rule :
Blue card = 4 squares forward
Red card = 6 squares backward
Yellow card = drawing a blue followed by a red
Spaces moved after drawing a yellow card:
Yellow equals :
Blue = + 4 squares ; then
Red = - 6 squares
Net total movement :
Blue + red
+4 + (-6)
4 - 6
- 2
2 squares backward
Answer:
1) 8 : 343
2) 42.875 or 42 ⅞
3) 4 : 49
4) 16ft²
Step-by-step explanation:
Volume of cube: s³
Surface area of cube: 6s²
_____________________
32ft^3 and 1372ft^3 →
32 : 1372 = 8 : 343
343 / 8 = 42 ⅞ = 42.875
s³ → 6s²
s³ = 8, s = 2, s² = 4.
s³ = 343, s = 7, s² = 49.
These are proportional so it is already in the simplest ratio so it is not necessary to multiply by 6.
s³ → 8 : 343
6s² → 4 : 49
(4 / 49) × 196ft² = 16ft²
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
secx =
, cosecx = 
cotx =
, tanx = 
Consider the left side
secA cosecA - cotA
=
×
- 
=
- 
= 
=
( cancel sinA on numerator/ denominator )
= 
= tanA = right side ⇒ proven
Answer:
308.647
Step-by-step explanation:
Its searchable pls mark brainliest.