Answer:
c
Step-by-step explanation:
this needs evaluation of Bella's income on every chore.
say when c = 1, d = 3.5*1+11= 14.5
c=2 d = 3.5*2+11= 18..evaluate for c=3,4,5.
with that it can be found that bella earns more than sweet t. so choice c
Answer:
![y = 0.25x + 4](https://tex.z-dn.net/?f=y%20%3D%200.25x%20%2B%204)
![(x,y) = (2,4.5)](https://tex.z-dn.net/?f=%28x%2Cy%29%20%3D%20%282%2C4.5%29)
Step-by-step explanation:
Given
![x = 2](https://tex.z-dn.net/?f=x%20%3D%202)
![y = 4.5](https://tex.z-dn.net/?f=y%20%3D%204.5)
Required
Make up a linear function
A linear function is represented as:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
Assume ![b = 4](https://tex.z-dn.net/?f=b%20%3D%204)
The equation becomes
![y = mx + 4](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%204)
Substitute
and
to solve for m
![4.5 = m*2 + 4](https://tex.z-dn.net/?f=4.5%20%3D%20m%2A2%20%2B%204)
![4.5 = 2m + 4\\](https://tex.z-dn.net/?f=4.5%20%3D%202m%20%2B%204%5C%5C)
Solve for m
![2m = 4.5 - 4](https://tex.z-dn.net/?f=2m%20%3D%204.5%20-%204)
![2m = 0.5](https://tex.z-dn.net/?f=2m%20%3D%200.5)
![m = 0.5/2](https://tex.z-dn.net/?f=m%20%3D%200.5%2F2)
![m = 0.25](https://tex.z-dn.net/?f=m%20%3D%200.25)
So, we have:
,
,
and ![y = 4.5](https://tex.z-dn.net/?f=y%20%3D%204.5)
becomes
![y = 0.25x + 4](https://tex.z-dn.net/?f=y%20%3D%200.25x%20%2B%204)
![(x,y) = (2,4.5)](https://tex.z-dn.net/?f=%28x%2Cy%29%20%3D%20%282%2C4.5%29)
X=2 it’s Honestly easy I just look at da missing number
Answer:
$0.65
Step-by-step explanation:
2.40-1.10=1.3
1.3/2=.65
Answer:
The probability that a vehicle would be involved in a tire-related accident is ![P(TRA)=8x10^{-5}](https://tex.z-dn.net/?f=P%28TRA%29%3D8x10%5E%7B-5%7D)
Step-by-step explanation:
We need to calculate the probability that a vehicule would be involved in a tire-related accident.
We know that, given a tire-related accident (TRA), the probability of it being deadly (D) is 0.05. That is:
![P(D|TRA)=0.05](https://tex.z-dn.net/?f=P%28D%7CTRA%29%3D0.05)
We also know that the probability of being involved in a deadly tire-related accident is 0.000004
. We can express that as the probability of having a TRA multiplied by the probability of it being deadly:
![P(D|TRA)*P(TRA)=0.000004](https://tex.z-dn.net/?f=P%28D%7CTRA%29%2AP%28TRA%29%3D0.000004)
Merging the two expressions we have:
![P(TRA)=0.000004/P(D|TRA)=0.000004/0.05=0.00008=8x10^{-5}](https://tex.z-dn.net/?f=P%28TRA%29%3D0.000004%2FP%28D%7CTRA%29%3D0.000004%2F0.05%3D0.00008%3D8x10%5E%7B-5%7D)