1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scilla [17]
3 years ago
13

Solve 2/3 = x/18 SOMEONE PLS HELP

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

x = 12

Step-by-step explanation:

what you have to do is cross multiply::

3x = 36

and then single the x out

x = 12

You might be interested in
Rachel rides her bike due east at 9 miles per hour. Amos rides his bicycle due north at 12 miles per hour. If they left from the
Svetach [21]

They will be 15 miles apart after one hour if they left the same point at the same time.

<h3>How do we measure and calculate the distance in Geometry?</h3>

The distance between two points in geometry can be calculated by using the Pythagoras theorem.

Mathematically, the Pythagoras theorem can be expressed as:

\mathbf{d = \sqrt{x^2 +y^2}}

where;

  • x and y are opposite and adjacent sides respectively.

\mathbf{d = \sqrt{(9)^2 +(12)^2}}

\mathbf{d = \sqrt{81+144}}

\mathbf{d = \sqrt{225}}

d = 15 miles  

Therefore, we can conclude that they will be 15 miles apart after one hour if they left the same point at the same time.

Learn more about calculating the distance between two points here:

brainly.com/question/7243416

#SPJ1

5 0
2 years ago
Berechne jeweils die Höhe der Pyramiden!<br>a) V = 140 cm3<br>G = 28 cm2<br>h = ?​
kozerog [31]

Answer:

untere Tabelle gibt an, wie Oberfläche und Volumen der Pyramide berechnet werden. Grundsätzlich gilt:

Oberfläche = Grundfläche + Mantelfläche

Volumen = Grundfläche · Pyramidenhöhe : 3

Generell ist darauf zu achten, dass mit unterschiedlichen Höhenangaben gerechnet wird. Für die Berechnung der Oberfläche wird die Höhe der schrägliegenden Seitendreiecke benötigt (Grafik unten: ha; hb). Für die Berechnung des Volumens wird die Höhe der Pyramide benutzt (Grafik unten: h).

JSXGraph v0.95 Copyright (C) see http://jsxgraph.org

ha = 5.83 cm

h = 5.00 cm

a = 6.00 cm

b = 6.01 cm

hb = 5.83 cm

V = 60.10 cm³

Ap = 106.11 cm²

AM = 70.05 cm²

AG = 36.06 cm²

 –  o  +  ←  ↓  ↑  → 

rechteckige Grundflächequadratische GrundflächeOberfläche = Grundfläche + Mantelfläche

OP = AG + AMOP = a · b + a · ha + b · hbOP = a² + a · ha · 2 Volumen = Grundfläche · h : 3

VP = AG · h : 3

VP = a · b · h : 3VP = a² · h : 3

Step-by-step explanation:

#semogamembantu

5 0
3 years ago
Find the probability of winning a lottery by selecting the correct six integers, where the order in which these integers are sel
lora16 [44]

Hey there,

The answer is A: 50

:)

5 0
3 years ago
Find the 52nd term for the following sequence. 16,6,-4,-14....
nikklg [1K]
I think it’s D, sorry if I’m wrong.
8 0
3 years ago
HELPPPPP PLEASEEEEEEEE I BEG YOU!!! SCHOOL IS ENDING SOON
Mars2501 [29]

Answer:

option c 1000

Step-by-step explanation:

...................

6 0
3 years ago
Read 2 more answers
Other questions:
  • In the equation y = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B3%7D%20" id="TexFormula1" title=" \frac{x}{3} " alt="
    12·1 answer
  • What is 3/5 written as a decimal?
    15·2 answers
  • Plz help me with numbers 7&amp;8 and there is a box below for answers and it needs to be and answer to that question
    11·1 answer
  • 7) A random sample of 40 men were asked how if they enjoyed watching sports more than movies and 64% percent reported that they
    13·2 answers
  • G(x)=26*((1)/(2))^(x)
    11·1 answer
  • There are two cube-shaped tanks. One of the tank has a 3 m side, while the other one has a side measuring half of the first one.
    5·1 answer
  • . Find the common factor of terms 5a4+15a3<br> -10a2
    5·1 answer
  • Please help <br><br>-45 &lt; 6s + 1 ​
    8·2 answers
  • HELP ME OUT!!!!
    6·2 answers
  • Can someone help me please
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!