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garri49 [273]
3 years ago
8

when copper wires are made, a copper rod is pulled into a narrower wire. Explain how metallic bonding allows this to happen

Chemistry
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

possibly because of the malleability of metals

Explanation:

In metallic bonding, electrons are delocalized and move freely among nuclei. When a force is exerted n the metal, the nuclei shift, but the bonds do not break, giving metals their characteristic malleability.

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maks197457 [2]
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6 0
3 years ago
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Draw the major organic product that is expected when cyclopentanecarboxylic acid is treated with each of the following reagents:
son4ous [18]

Answer:

a. Sodium cyclopentanecarboxylate

b. No reaction

Explanation:

In this case, in the cyclopentanecarboxylic acid we have a <u>carboxylic acid</u> functional group. Therefore we have an "acid". The acids by definition have the ability to produce hydronium ions (H^+).

With this in mind, for molecule a. we will have an <u>acid-base reaction</u>, because NaOH is a base. When we put together an acid and a base we will have as products a <u>salt and water</u>. In this case, the products are  Sodium cyclopentanecarboxylate (the salt) and water.

For the second molecule, we have the hydronium ion  (H^+). This ion can not react with an acid. Because, the acid will produce the hydronium ion also, so <u>a reaction between these compounds is not possible.</u>

See figure 1

I hope it helps!

8 0
3 years ago
Determine whether or not the mixing of each pair of solutions results in a buffer. Show all work!
tia_tia [17]

Answer:

a) Acidic buffer

b) No buffer

c) Acidic buffer

d) Basic buffer

e) Basic buffer

Explanation:

a) 75.0 mL of 0.10 M HF ; 55.0 mL of 0.15 M NaF -Acidic buffer

Mixing of 75.0 mL of 0.10 HF and 55.0 mL of 0.15 mL NaF results in acidic buffer. HF/NaF is a buffer of weak acid and its conjugate base. F- is the conjugate base of acid,HF.

b.) 150.0 mL of 0.10 M HF ; 135.0 mL of 0.175 M HCl-No buffer

Mixing HF and HCl will not results in a buffer. Both are acids, and no conjugate base is present.

c.) 165.0 mL of 0.10 M HF ; 135.0 mL of 0.050 M KOH-Acidic buffer

HF reacts with KOH to form KF. F- is a conjujate base of HF. As volume and concentration of HF is more than KOH, therefore, HF will remain after reaction with KOH. HF/KF will be a buffer of weak acid and its conjugate base.

d.) 125.0 mL of 0.15 M CH3NH2 ; 120.0 mL of 0.25 M CH3NH3Cl -Basic buffer

CH3NH2/CH3NH3+ is a buffer of weak base and its conjugate acid.

e.) 105.0 mL of 0.15 M CH3NH2 ; 95.0 mL of 0.10 M HCl-Basic buffer

CH3NH2 is a weak base and HCl is a strong acid. CH3NH2 reacts with HCl to form its conjugate acid CH3NH3+. Volume and concentration of CH3NH2 is more as compared to HCl and hence, will remain in the soution after reactionf with HCl.

CH3NH3+/CH3NH2 is a buffer of weak base and its conjugate acid.

6 0
4 years ago
What does the law of the conservation of momentum state?
UNO [17]

Answer:

The conservation of momentum states that, within some problem domain, the amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion. ... Momentum is conserved in all three physical directions at the same time.

6 0
3 years ago
The temperature of a sample of gas at 8.5 atm and 59.2 °C increases to 140.0 °C. If the
labwork [276]

Answer:

since that's the closest option we have

10.6atm

Explanation:

Since volume is constant

P1/T1 = P2/T1

P1 =8.5atm

T1 = 59.2°C = 332.2k

T2 = 140°C = 413k

P2 = ?

8.5/332.2 = P2/413

0.026 = P2/413

P2 = 0.026 x 413

P2 = 10.74atm

5 0
3 years ago
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