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krek1111 [17]
3 years ago
10

In three basketball games over a weekend, 125,429 people came to watch. The next weekend , 86,353 people came to watch the games

. How many people total watched the six baseball game.
Mathematics
1 answer:
Tems11 [23]3 years ago
3 0
  125,429
+  86,353
__________
211,845

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An amusement park offers an entrance fee discount of 20% to children under 6 years of age and seniors 65 or older. What is the r
Temka [501]

Answer:

  [0, 6) ∪ [65, ∞)

Step-by-step explanation:

Ages under 6 will be in the interval [0, 5], or in the interval [0, 6), as you may wish.

Ages 65 or older will be in the interval [65, ∞).

The union of these two intervals is ...

  [0, 6) ∪ [65, ∞)

5 0
3 years ago
Write as a mathematical equation. The product of 5 and x is 25.
pickupchik [31]

answer:

5x=25

Divide 5 from both sides

5x/5=25/5

x=5

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3 years ago
A circus tent is cylindrical upto a height of 3.3 m and conical above it if the diameter of the base is 100m and slant height of
Rina8888 [55]

Total cost of canvas required in making the tent is rupees 79128

<em><u>Solution: </u></em>

Given:

Height of the cylindrical tent = h = 3.3 m

Diameter of it's base = d = 100m

radius = \frac{diameter}{2} = \frac{100}{2} = 50

r = 50 m

<em><u>Curved surface area of cylinder:</u></em>

C.S.A = 2 \pi rh

C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2

Thus Curved surface area of cylinder = 1036.2 square meter

<em><u>Curved surface area of cone:</u></em>

C.S.A = \pi rl

C.S.A = 3.14 \times 50 \times 56.4 = 8854.8

Thus Curved surface area of cone = 8854.8 square meter

<em><u>Total curved area of tent:</u></em>

⇒ curved area of cone + curved area of cylinder

\rightarrow 8854.8 + 1036.2=9891

Thus total curved area of tent = 9891 square meter

<em><u>find total cost of canvas required in making the tent:</u></em>

The cost of canvas is 8 rupees per square meter

\rightarrow \text{total cost } = 9891 \times 8 = 79128

Thus total cost of canvas required in making the tent is rupees 79128

7 0
3 years ago
Triangle PQR where P(1,4), Q(-3,-4),R(7,k) is right-angled at Q. find the value of k
NikAS [45]

Answer:

k = -9.

Step-by-step explanation:

As the triangle is right-angled at Q, by Pythagoras:

PR^2 = PQ^2 + RQ^2

So, substituting the given data and using the distance formula between 2 points:

(7 - 1)^2 + (k - 4)^2 =  (-4-4)^2 + (-3-1)^2 + (7 - (-3))^2 + (k - (-4))^2

36 + (k - 4)^2 = 64 + 16 + 100 + ( k + 4)^2

(k - 4)^2 - (k + 4)^2 = 180 - 36

k^2 - 8k + 16 - (k^2 + 8k + 16) = 144

-16k = 144

k = -9.

8 0
3 years ago
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EleoNora [17]

Answer:

should be 89 since it's directly across

8 0
3 years ago
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