<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,
As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then 
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.
Answer:
The two possible cases are
(i) the base angles are each 40° and the vertex angle is 100°,
(ii) the base angles are each 70° and the vertex angle is 40°.
Step-by-step explanation:
Answer:
4 + 2i
Step-by-step explanation:
First distribute;
7 - 3 - 4i + 6i
= 4 + 2i
Answer:
Pair 2.
Step-by-step explanation:
For the volumes to be the same the base areas must also be the same.
For Pair 2 the areas are 25π and 24π while the other 2 pairs have both base areas = 25π.
