Answer:
the picture is blank resend me the question and i’ll be right on it
X=275+55= 330 biked
y=275-55= 220 bus
You have to calculate the expected value of pulling any number of good batteries.
There are 3 bad batteries (B) and seven good batteries (G)
If you pull two batteries the possible number of good batteries you can get are 0, 1 and 2.
GB, BG, GG, and BB
two chances for getting 1, one chance for getting two, and one chance for getting zero.
In order to calculate the expected value you have to first calculate the values of all the possibilities.
(GB = 7/10 x 3/10) (BG = 3/10 x 7/10) (GG = 7/10 x 7/10) (BB = 3/10 x 3/10)
Then take these answers and multiply them by the number of good batteries they each contain and add. (GB is 1 good battery, GG is two, etc.)
1(.21) + 1(.21) + 2(.49) + 0(.09)
The result is 1.4
The expected value of good batteries is 1.4
Given :
- CD is the altitude to AB.
A = 65°.
To find :
- the angles in △CBD and △CAD if m∠A = 65°
Solution :
In Right angle △ABC,
we have,
=> ACB = 90°
=>
CAB = 65°.
So,
=>
ACB +
CAB+
ZCBA = 180° (By angle sum Property.)
=> 90° + 65° +
CBA = 180°
=> 155° +
CBA = 180°
=>
CBA = 180° - 155°
=>
CBA = 25°.
In △CDB,
=> CD is the altitude to AB.
So,
=>
CDB = 90°
=>
CBD =
CBA = 25°.
So,
=>
CBD +
DCB = 180° (Angle sum Property.)
=> 90° +25° +
DCB = 180°
=> 115° +
DCB = 180°
=>
DCB = 180° - 115°
=>
DCB = 65°.
Now, in △ADC,
=> CD is the altitude to AB.
So,
=>
ADC = 90°
=>
CAD =
CAB = 65°.
So,
=>
ADC +
CAD +
DCA = 180° (Angle sum Property.)
=> 90° + 65° +
DCA = 180°
=> 155° +
DCA = 180°
=>
DCA = 180° - 155°
=>
DCA = 25°
Hence, we get,
DCA = 25°
DCB = 65°
CDB = 90°
ACD = 25°
ADC = 90°.
Answer:
The correct option is A.
Step-by-step explanation:
Total number of students at the school is 2,500.
In the given pi chart Pink, Yellow and Sky Blue color represent the percentage of students that under reported, accurately reported, and over reported their heights respectively.
From the graph we can conclude that the yellow portion is approximately one fifth of whole circle. It means the number of students that accurately reported their height is one fifth of total number of students.

Therefore the number of students that accurately reported their height is 500. Option A is correct.