The sine of 30° is 0.5 .
Angles don't have y-values, and neither do their sines. But
IF you draw a graph of the sine function, AND the angles
(the independent variable) are marked off on the x-axis of
the graph, AND the value of the sine function of each angle
(the dependent variable) is marked off on the y-axis of the
graph, THEN the y-value corresponding to the angle of 30°
would be displayed as 0.5 .
An exterior angle is an angle supplementary to one of the interior angles.
In other words, an exterior angle is the angle between one of the sides, and the extension of an adjacent side.
In the given diagram, the angle D is measured from one of the sides, but not to the extension of an adjacent side.
Therefore angle D is not an exterior angle.
Option D is the correct one!
Answer:
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The measure of the external angle is the semi-difference of the arches it covers.
so
![m\angle GET=\frac{1}{2}[arc\ TN-arc\ TG]](https://tex.z-dn.net/?f=m%5Cangle%20GET%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20TN-arc%5C%20TG%5D)
Remember that the diameter divide the circle into two equal parts
In this problem
TN is a diameter
we have
----> because is half the circle (TN is a diameter)
---> is given
substitute
![m\angle GET=\frac{1}{2}[180^o-46^o]=67^o](https://tex.z-dn.net/?f=m%5Cangle%20GET%3D%5Cfrac%7B1%7D%7B2%7D%5B180%5Eo-46%5Eo%5D%3D67%5Eo)
Answer:
WASSUP
Step-by-step explanation:
