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3 years ago

Car went grocery shopping and bought chicken for

Mathematics

1 answer:

lord [1]3 years ago

6 0

The total cost of everything is $18.08

$20 minus $18.08

The answer is $2.02

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In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find: AC, if CD = 6√2 in.

klio [65]

Answer:

AC = 12 units.

Step-by-step explanation:

Δ ACD is right-angled. ( as CD ⊥ AB).

cos 45° = CD / AC = 6√2 / AC

AC = 6√2 / cos 45°

AC = 6√2 / 1 /√2

= 6√2 *√2

= 6 * 2

= 12 (answer)

HOPE THIS HELPED ;3

5 0

3 years ago

Find f^3(x) for f(x)=4/x^2

vaieri [72.5K]

Answer:

f³(x) = 64/x⁶

Step-by-step explanation:

f³(x) = (f(x))³ = (4/x²)³ = 4³/(x²)³

f³(x) = 64/x⁶

_____

The applicable rules of exponents are ...

(a/b)^c = (a^c)/(b^c)

(a^b)^c = a^(bc)

7 0

3 years ago

Union City Bakery uses a chocolate chip muffin recipe that yields 1/2 cup of milk for every batch of 12 chocolate chip muffins.

NeX [460]

You need 1/24 of a cup to make one muffin you would need one cup of milk to make 24 muffins

7 0

3 years ago

The situation is as follows: Smart phones have changed the world and how we spend our time. A group of researchers at BYU want t

Scilla [17]

Answer:

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

Step-by-step explanation:

Confidence interval normal

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.96}{2} = 0.02$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.02 = 0.98$ , so Z = 2.054.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.054\frac{54}{\sqrt{430}} = 5.35$

The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes

The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

8 0

2 years ago

F(x) = (3 + x1.2)x+3.8 at x = 4.3

Anna007 [38]

Hope this helped you

3 0

2 years ago