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zepelin [54]
2 years ago
15

Vertical angles have been formed by two lines. If one angle is 5x + 7 and the other is 22°, find the value of x.

Mathematics
1 answer:
valkas [14]2 years ago
4 0

Answer:

x = 3

Step-by-step explanation:

Measure of vertical angles are equal.

Therefore,

(5x + 7)° = 22°

5x + 7 = 22

5x = 22 - 7

5x = 15

x = 15/5

x = 3

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Can someone plz help me with this one problem plzzzzz!!!!!
lesantik [10]

Answer:

5 = 60.    6 = 72.      8 = 96

Step-by-step explanation:

60 = 12 x 5

72 = 12 x 6

84 = 12 x 7

96 = 12 x 8

6 0
2 years ago
Read 2 more answers
Whats x? i don’t understand
rewona [7]

Answer:

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try! A variable doesn't have to be "x", it could be "y", "w" or any letter, name or symbol. See: Variable.

Step-by-step explanation:

8 0
2 years ago
What is the term, coefficient, constant, and factor of 1/2(base1 + base2)h? (Formula used to find area of trapezoid)
vovangra [49]

Answer:

i. Term = \frac{b_{1}h }{2} + \frac{b_{2}h }{2}

ii. Coefficient = \frac{1}{2}

iii. Constant = \frac{1}{2}

iv. Factor = \frac{h}{2}

Step-by-step explanation:

A trapezoid is a quadrilateral which has its base parallel to the opposite side. It's area can be determined by;

Area of trapezium = \frac{1}{2} (b_{1} + b_{2})h

Where b_{1} is the measure of length of its fist base,  b_{2} is the measure of its second base and h is its height.

Considering the given question,

Term = \frac{b_{1}h }{2} + \frac{b_{2}h }{2}

Coefficient = \frac{1}{2}

Constant = \frac{1}{2}

Factor = \frac{h}{2}

6 0
2 years ago
Find the average rate of change of f(x)=2x^2-7x from x=2 to x=6
scoundrel [369]

Answer:

Step-by-step explanation:

The average rate of change of a function f between a and b (a< b) is :

R =[f(b)-f(a)] ÷ (a-b)

●●●●●●●●●●●●●●●●●●●●●●●●

Let R be the average rate of change of this function

f(6) = 2×6^2 - 7×6 = 72-42 = 30

f(2) = 2×2^2 - 7×2 = 8-14 = -6

R = [f(6) - f(2)]÷ (6-2)

R = [30-(-6)] ÷ 4

R = -36/4

R = -9

■■■■■■■■■■■■■■■■■■■■■■■■■

The average rate of change of this function is -9

8 0
3 years ago
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A path 2.5m wide is running outside a square field whose side is 45m. Determine the area of the path.
aliya0001 [1]

Answer:

The area of the path would be 231.25 squared meters.

Step-by-step explanation:

Consider the path as 45m (the field's area), then add 2.5m to all of the sides. You'll get 47.5m on all sides. Then you do 47.5² to get 2256.25 squared meters. After that, you'll remove the area of the squared field. To do this, do 45m². By doing this, you'll get 2025 squared meters. Lastly, to finish up the question, do 2256.25 - 2025. This would get you 31.25 squared meters, the answer.

4 0
3 years ago
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