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3 years ago

Will mark brainliest with ONE question!!^^^^^^^^

Mathematics

2 answers:

Blababa [14]3 years ago

7 0

Answer:

c + 0.5b =700 and c + b =1,000 I think

12345 [234]3 years ago

7 0

Answer:

c+b=1000

Step-by-step explanation:

This problem can be solved by process of elimination. If the end weight is 1000, then at the equal sign, it should also be 1000. Since the last option is the only one with 1000, then it would be the only correct option.

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Sam received a 15 percent tip for delivering pizzas. If the cost of the pizzas was $247.62, what was the total amount he collect

saveliy_v [14]

247.62 x 0.15 = 37.143

round to $37.14

I hope that helped :)

4 0

3 years ago

Simplify the following: (-83)2

Anika [276]

The answer is -166, your welcome

8 0

3 years ago

The temperature at the south pole was 6 degrees at 8am. At 3 pm it was -18 degrees. By how many degrees did the temperature drop

olga2289 [7]

Answer:

$24\°$

Step-by-step explanation:

we know that

To determine how many degrees drop the temperature, find out the absolute value of subtract the temperature at 8 am from the temperature at 3 pm.

$\left|-18-6\right|=24\°$

7 0

3 years ago

A log is 20 m long, correct to the nearest metre.

Marat540 [252]

Answer:

222 fence posts

Step-by-step explanation:

Since the log is 20 m long, correct to the nearest metre and has to be cut into fence posts which must be 90 cm long, correct to the nearest 10 centimetres, there can be x fence posts 90 cm long.

So, we have x × 90 cm = 20 m

x × 0.9 m = 20 m

x = 20 m/0.9 m

x = 222.22

x ≅ 222 fence posts

So, the largest number of fence posts that can possibly be cut from the log is 222 fence posts.

4 0

3 years ago

PLEASE HELP MEEEE HURRRY!!! :)

sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

$\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}$

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

$\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}$ First, I swapped the first and third rows.

$\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}$ Leading coefficient of row 2 canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}$ The start value of row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}$ Matrix rows 2 and 3 were swapped.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}$ Leading coefficient in row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}$

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

$\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}$

The positioning of the zeros indicated that there was no solution!

<u><em>Hope that helps!</em></u>

6 0

3 years ago