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2 years ago

YOU WILL GET MARKED BRAINLIEST:)

Mathematics

2 answers:

Aleks04 [339]2 years ago

7 0

Answer:

Z = 2

Step-by-step explanation:

This tape diagram is split into two equal parts.

Since 2 and 2 are equal, and since 2 and 2 have a sum of 4, then z is equal to 2.

Mandarinka [93]2 years ago

4 0

Answer:

z = 2

Step-by-step explanation:

if two z go into 4 then it's 2 because 2 is the only number that goes into 4 twice

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What is the value of 6 + 2x when x = 5? (A) 4 (B) 13 (C)16 (D) 40

jasenka [17]

so x=5

substituting for x in the equation we get:

$6+2 \times 5 \\ = 6 + 10 = \\ = 16$

Ans C: 16

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2 years ago

Catron evaluates the expression (negative 9) (2 and two-fifths) using the steps below.

Vlad [161]

Answer:

Catron's error is

"She did not follow order of operations"

Step-by-step explanation:

Catron evaluates the expression (negative 9) (2 and two-fifths)

That expression can be written as below

$(-9)(2\frac{2}{5})$

Catron's error is

"She did not follow order of operations"

The corrected steps are

Step1: Given expression is $(-9)(2\frac{2}{5})$

Step2: Convert mixed fraction into improper fraction

$(-9)(2\frac{2}{5})=(-9)(\frac{12}{5})$

Step3: Multiplying the terms

$(-9)(2\frac{2}{5})=-7\frac{-108}{5}$

Therefore solution $(-9)(2\frac{2}{5})=-7\frac{-108}{5}$

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2 years ago

Read 2 more answers

here’s a graph of the equation x + 3y = 6 select all coordinates pairs that represent a solution to the equation A) 0,2 B) 0,6 C

Afina-wow [57]

Answer:

(0,2) (3,1)

Step-by-step explanation:

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2 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

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3 years ago