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Anettt [7]
2 years ago
7

Adam jogs at an average speed of 10km/h from his house to the airport. The airport is 7km away from his house. At what time must

Adam leave his house in order for him to reach the airport at 7:20 am.
Mathematics
1 answer:
mote1985 [20]2 years ago
8 0

Answer:

6:38am

Step-by-step explanation:

From the question we are told that

Average speed V_{avg}=10km/h

Distance traveled d=7km

Generally the velocity across a distance is mathematically given given as V=d/t

10=\frac{7}{t}

t=0.7h\\t=42minutes

Therefore

7:20-42 minutes =6:38am

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