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Sergeu [11.5K]
3 years ago
15

Which of the following shows the additive inverse of 4?*

Mathematics
1 answer:
spayn [35]3 years ago
3 0
C is the correct answer I think
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Can anyone offer HELP!
Temka [501]
Your answer would be C.
I just plugged in the numbers on a piece of paper and they all fit :)
5 0
3 years ago
probability distribution that meets these requirements: 1) the procedure has a fixed number of trials; 2) the trial must be inde
loris [4]

Answer:  The required probability distribution is BINOMIAL DISTRIBUTION.  

Step-by-step explanation:  We are given to state the probability distribution that meets the following requirements :

1) the procedure has a fixed number of trials;

2) the trial must be independent;

3) each trial must have all outcomes classified into two categories;

4) the probability of a success remains the same in all trials

The given requirements are fulfilled by only one type of probability distribution, that is BINOMIAL DISTRIBUTION.

Only the Binomial Distribution has a fixed number of independent trials, each trial has only two possible outcomes (success and failure) and the probability of success remains same in all trials.

Thus, the required probability distribution is BINOMIAL DISTRIBUTION.  

5 0
3 years ago
Consider the system of linear equations. 7 x + 16 y = negative 2. 9 x minus 4 y = 22. To use the linear combination method and a
bija089 [108]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Hello someone help please <br>what is the product of (cosA+2)(cosA-3)​
svetoff [14.1K]

Answer:

cos²A - cosA - 6

Step-by-step explanation:

Given

(cosA + 2)(cosA - 3)

Each term in the second factor is multiplied by each term in the first factor, that is

cosA(cosA - 3) + 2(cosA - 3) ← distribute both parenthesis

= cos²A - 3cosA + 2cosA - 6 ← collect like terms

= cos²A - cosA - 6

7 0
3 years ago
Determine the transformation used to create triangle PMK
Mkey [24]
There is no image. I would love to help. but I can't see the image or figure
7 0
3 years ago
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