Question

Reduce the fraction -20t^5u^2v^3/ 48t^7u^4v

Answer 1

$\dfrac{-20t^5u^2v^3}{48t^7u^4v}=\dfrac{-20}{48}\cdot\dfrac{t^5u^2v^2v}{t^5t^2u^2u^2v}=-\dfrac{5}{12}\cdot\dfrac{v^2}{t^2u^2}=-\dfrac{5v^2}{12t^2u^2}$

$Used:\\\\a^n\cdot a^m=a^{n+m}$