Reduce the fraction -20t^5u^2v^3/ 48t^7u^4v

1 answer:

6 0

$\dfrac{-20t^5u^2v^3}{48t^7u^4v}=\dfrac{-20}{48}\cdot\dfrac{t^5u^2v^2v}{t^5t^2u^2u^2v}=-\dfrac{5}{12}\cdot\dfrac{v^2}{t^2u^2}=-\dfrac{5v^2}{12t^2u^2}$

$Used:\\\\a^n\cdot a^m=a^{n+m}$

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Colby is making a home video consisting of a 5-minute introduction followed by several short skits. Each skit is 6 minutes long.

givi [52]

<h2>Hello!</h2>

The answer is: There are a total of 16 skits in the video.

From the statement, we know that the total length of the video is 101 minutes and it contains a 5-minute introduction, the rest of the minutes are short skits (which are 6 minutes long each one).

So, we need to write the following equations:

First equation:

$TotalDuration=Introduction+n*Skit$

Second equation:

$Skit=6Minutes$

Where,

$TotalDuration=101Minutes\\Introduction=5Minutes\\n=NumberOfSkits\\Skit=6Minutes$

So, replacing and substituting the second equation into the first equation we have:

$101Minutes=5Minutes+n*6Minutes\\n*6Minutes=101Minutes-5Minutes\\n*6Minutes=96Minutes\\n=\frac{96Minutes}{6Minutes}=16$

So, there are a total of 16 skits in the video.

Let's prove it substituting "n" into the first equation:

$101Minutes=5Minutes+16*6minutes\\101Minutes=5Minutes+96Minutes\\101Minutes=101Minutes$

Have a nice day!

8 0

3 years ago

By driving 8 mph faster than Bob, John can make a 230 mile trip in one half hour less. How fast does Bob drive on the trip? Roun

____ [38]

Answer: The speed of Bob is 56.8 km/hr.

Step-by-step explanation:

Let the speed of Bob be 'x'.

Let the speed of John be 'x-8'.

Distance covered = 230 miles

time = $1\dfrac{1}{2}=\dfrac{3}{2}\ hr$

According to question, we get that

$\dfrac{230}{x}-\dfrac{230}{x+8}=\dfrac{3}{2}\\\\230\dfrac{x+8-x}{x(x+8)}=\dfrac{3}{2}\\\\\dfrac{230\times 8}{x^2+8x}=\dfrac{3}{2}\\\\\dfrac{1840}{x^2+8x}=\dfrac{3}{2}\\\\1840\times 2=3x^2+24x\\\\3680=3x^2+24x\\\\3x^2+24x-3680=0\\\\x\approx 56.8\ km/hr$