We want to find the mean of two elements in a set, given that we know the other elements of the set and the mean of the whole set.
The answer is: -490
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For a set with N elements {x₁, x₂, ..., xₙ} the mean is given by:
Here we know that:
- The mean of the set is 0.
- The set has 1000 elements.
- 998 of these elements are ones, the other two are A and B.
We want to find the mean of the values of A and B.
First, we can start by writing the equation for the mean:
We can rewrite this as:
And we have 998 ones, then:
Now we have B isolated.
With this, the mean of A and B can be written as:
So we can conclude that the mean of the other two numbers is -490.
If you want to learn more, you can read:
brainly.com/question/22871228
Answer:
- B. BC = 18 so ∆ABC ～ ∆DEF by SAS
Step-by-step explanation:
So, ∆ABC ～ ∆DEF by SAS.
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Answer:
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Step-by-step explanation:
Let's begin by evaluating f(x) using the value of 3: f(x) = 2x2 - 4x - 4 (original function) f(3) = 2(3)2 - 4(3) - 4 (plugging in 3 for x) f(3) = 2 (computed result) Now let's evaluate g(x) using the value of 3: g(x) = 4x - 7 (original function) g(x) = 4(3) - 7 (plugging in 3 for x) g(x) = 5 (computed result) Finally, we'll sum our results: (f + g)(3) = 2 + 3 (add f(3) and g(3)) <span>(f + g)(3) = 5 (final answer)</span>
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hope this helps!
