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irakobra [83]
3 years ago
13

Which of the following terms correctly describe the object below? Check all that apply

Mathematics
2 answers:
ruslelena [56]3 years ago
8 0
Where is the object
RideAnS [48]3 years ago
8 0
Where is the object
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A trucker traveled an average of 48.6 miles each hour on a 583.2-mile trip. For how many hours did the trucker travel?
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Divide 583.2 by 48.6 to get your answer, 12 hours.
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Convert y=9 from rectangular to polar form
Crazy boy [7]

Answer:

r = 9/sin Ф or r = 9 csc Ф

Step-by-step explanation:

The polar form is represented as:

x = r cos Ф and

y = r sin Ф

We are given:

y = 9

Putting value in y = r sin Ф

9 = r sin Ф

=> r = 9/sin Ф

1/sin Ф = csc Ф

or, r = 9 csc Ф

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2 years ago
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Write out the sample space for the given experiment. Use the following letters to indicate each choice: O for olives, M for mush
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Answer: He can make 36 different salds

Step-by-step explanation:

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3 years ago
Solve<br> *<br> x + 12/2=<br> 3(x + 7)
zheka24 [161]

Step-by-step explanation:

x+6=3x+21

2x=-15

x=-7.50

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3 years ago
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Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
3 years ago
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