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Rasek [7]
3 years ago
13

Please show work i would appreciate it ​

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

a) x = 14

b) The perimeter of △QRS is 77 units.

Step-by-step explanation:

a) Due to the question asking for a solution using the Triangle Proportionality Theorem, it is assumed that △RQS is similar to the smaller triangle inside it.

Let us define the point at which the line inside △RQS meets line RQ as T, and the point at which that same line meets line RS as V.

Hence, △RTV ~ △RQS.

According to the Triangle Proportionality Theorem:

\frac{RT}{RQ} = \frac{TV}{QS} = \frac{VR}{SR}

Hence, we can substitute all values that we know from the diagram:

\frac{2x - 2}{2x - 2 + 13} = \frac{TV}{17} = \frac{21 - 7}{21}

After getting this information, all we have to do is simplify and solve the equation:

\frac{2x - 2}{2x - 2 + 13} = \frac{21 - 7}{21}

\frac{2x - 2}{2x + 11} = \frac{14}{21}

\frac{2x - 2}{2x + 11} = \frac{2}{3}

3(2x - 2) = 2(2x + 11)

6x - 6 = 4x + 22

6x - 4x = 22 + 6

2x = 28

x = 14

To verify this answer, we can plug in the value of x into the equation:

\frac{2(14) - 2}{2(14) - 2 + 13} = \frac{2}{3}

\frac{26}{39} = \frac{2}{3}

\frac{2}{3} = \frac{2}{3}

Hence, after verification, we can get the answer: x = 14.

--------------------------------------------------------------------------------------------------------------

b) To find the perimeter of △QRS, all we have to do is to add all the lengths of the sides of △QRS together.

Hence, 2(14) - 2 + 13 + 17 + 21

= 28 - 2 + 13 + 17 + 21

= 77 units

Therefore, the perimeter of △QRS is 77 units.

Hope this helped!

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I really need this help
IRISSAK [1]

Answer:

area: 454.2 sq.cm

perimeter: 77.7 cm

Step-by-step explanation:

to find area, find the area of all the separate shapes and add them together:

semi-circle:

radius is 12 cm

area = \frac{\pi (12)^2\\}{2} = 226.2 sq.cm

separate the trapezoid into two right triangles and a rectangle.

area for triangles:

\frac{1}{2}(5)(12) = 30

30 x 2 = 60 sq.cm (since there are two triangles)

area for rectangle:

12 x 14 = 168 sq.cm

area of whole shape: 226.2 + 60 + 168 = 454.2 sq.cm

for perimeter, just add the length of the exterior sides together.

we have some unknown sides, such as the semicircle and the sides of the trapezoid

we can find the hypotenuse of the triangles we used earlier to find the sides of the trapezoid with pythagorean theorem

5^2 + 12^2 = c^2

25 + 144 = c^2

169 = c^2

\sqrt{169} =\sqrt{c^2}

c = 13 cm

to find the outside perimeter of the semi-circle, solve as if you were finding the circumference of a normal circle and divide it in half

\frac{2\pi12}{2} = 37.7 cm

now add it all up:

14 + 13 + 13 +37.7 = 77.7

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