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2 years ago

Find the solution by graphing the equations pls help

Mathematics

1 answer:

lilavasa [31]2 years ago

4 0

Answer:

graph these
y = 2x + 2
y = 2x - 3

Step-by-step explanation:

2x - y = -2
2x - y = 3

convert to y intercept form
first
2x - y = -2
-y = -2x - 2
y = 2x + 2
second
2x - y = 3
-y = -2x + 3
y = 2x - 3

you are left with
y = 2x + 2
y = 2x - 3
i cannot graph these for you, but i assume you know how, there is no solution because the lines are parallel

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If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that

Ivan

Answer:

$\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}$

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

Given :-

• $\sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}$

To Prove :-

• $\sf\implies cos2A =\dfrac{\sqrt3}{2}$

Proof :-

We know that ,

$\sf\implies cos2A = 1 - 2sin^2A$

Therefore , here substituting the value of sinA , we have ,

$\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2$

Simplify the whole square ,

$\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}$

Add the numbers in numerator ,

$\sf\implies cos2A = 1-2\times \dfrac{4-2\sqrt3}{8}$

Multiply it by 2 ,

$\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}$

Take out 2 common from the numerator ,

$\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}$

Simplify ,

$\sf\implies cos2A = 1 -\dfrac{ 2-\sqrt3}{2}$

Subtract the numbers ,

$\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}$

Simplify,

$\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }$

Hence Proved !

8 0

2 years ago

Which matrix equation represents the system of equations? {-x+ 2y = 0 y= -2

Snowcat [4.5K]

We are given a system of equations,

$\begin{cases}-x+2y=0\\y=-2\\ \end{cases}$

This will translate into a 2x2 matrix of coefficients (because 2 equations and 2 unknowns),

$\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}$

The matrix will then be applied to the vector (lower dimensions on top),

$\begin{bmatrix}x\\y\\ \end{bmatrix}$

And the result vector will be whats on the other side of equals sign,

$\begin{bmatrix}0\\-2\\ \end{bmatrix}$

So to put everything together,

$\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}\begin{bmatrix}x\\y\\ \end{bmatrix}=\begin{bmatrix}0\\-2\\ \end{bmatrix}$

Hope this helps :)

6 0

2 years ago

Consider the following sets.

Andrews [41]

A = {x ≥ 3}, B = {x ≤ 1}

So A∪B = {x ≥ 3 or x ≤ 1}

So for x ⊆(1,3), A∪B = ∅

Apparently, (1,3) covers the first option, a will be the answer

6 0

3 years ago

Read 2 more answers

Help!! i also need the work please!!

alex41 [277]

Answer:

1. $1.40

2.$1.75

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=8%20%5Csqrt%7B72%7D%20" id="TexFormula1" title="8 \sqrt{72} " alt="8 \sqrt{72} " align="absmid

Ghella [55]

Answer:

$8 \sqrt{72} = 8 \sqrt{3 \times 3 \times 2 \times 2 \times 2} \\ = 8 \times 3 \times 2 \times \sqrt{2} = 48 \sqrt{2}$

<h2>48√2 is the right answer.</h2>

7 0

2 years ago