Answer:
m/7
Step-by-step explanation:
because m divided by seven is m/7 so that is the answer
Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that 
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.




IQ scores of at least 130.81 are identified with the upper 2%.
Answer:
-69/200
Step-by-step explanation:
-0.345 is in decimal form.
In Fractional form (p/q)
=-345/1000
To simplify, divide the numerator and the denominator by the G.C.D(Greatest Common Divisor) of p and q.
In this case,G.C.D of 345 and 1000 is 5.
Simplified form=-69/200 [ANS]
Answer:
-3y +12 = -48
-3y = -60
y = -60/-3
y = 20
Step-by-step explanation:
Step-by-step explanation:
It would be
9+6 because 0.50 is a dollar so if u multiply by 6 and add the 9 the equation would be 9+6.......
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