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2 years ago

6

the first third and sixth terms of an arithmetic sequence are shown. what is the common difference between consecutive terms in

the arithmetic sequence 2,_,8,_,_,17,

1 answer:

diamong [38]2 years ago

8 0

Answer:it is going up by 3 each time

Source:trust me bro

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(56 + 8 x 2) divided by 9

vladimir2022 [97]

Answer:8

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3 years ago

F(x, y, z) = yzexzi + exzj + xyexzk,c: r(t) = (t2 + 4)i + (t2 − 1)j + (t2 − 2t)k, 0 ≤ t ≤ 2(a) find a function f such that f = ∇

exis [7]

$\nabla f(x,y,z)=\mathbf f(x,y,z)=yze^{xz}\,\mathbf i+e^{xz}\,\mathbf j+xye^{xz}\,\mathbf k$

$\dfrac{\partial f(x,y,z)}{\partial x}=yze^{xz}$
$\implies f(x,y,z)=\displaystyle\int yze^{xz}\,\mathrm dx=\dfrac{yz}ze^{xz}+g(y,z)$
$f(x,y,z)=ye^{xz}+g(y,z)$

$\dfrac{\partial f(x,y,z)}{\partial y}=e^{xz}=e^{xz}\dfrac{\partial g(y,z)}{\partial y}$
$\implies\dfrac{\partial g(y,z)}{\partial y}=0\implies g(y,z)=h(z)$
$f(x,y,z)=ye^{xz}+h(z)$

$\dfrac{\partial f(x,y,z)}{\partial z}=xye^{xz}=xye^{xz}+\dfrac{\partial h(z)}{\partial z}$
$\implies\dfrac{\partial h(z)}{\partial z}=0\implies h(z)=C$
$f(x,y,z)=ye^{xz}+C$

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3 years ago

Plz help me plz plz plz asap PLZ PLZ PZL HELLLP

fiasKO [112]

Answer:

22x + 100 = 25x + 70, 10 yards

Step-by-step explanation:

Set the number of square yards of carpeting as x.

So, the cost of Country Carpets is: 22 * x + 100

And the cost of City Carpets is: 25 * x + 70.

In order for the costs to be the , the equations need to be equal.

22x + 100 = 25x + 70

Subtract 22x from both sides.

100 = 3x + 70

Subtract 70 from both sides.

3x = 30

x = 10

10 square yards

7 0

2 years ago