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3 years ago

Please help!! Thanks!

Mathematics

2 answers:

vladimir2022 [97]3 years ago

4 0

I hope this helps you

1) DC=60

AD=AC=60/2=30

AB=BC=30/2=15

DB=DA+AB=30+15=45

2) RQT is right triangle we can find the side

6^2+8^2=RT^2

36+64=RT^2

RT=10

xz_007 [3.2K]3 years ago

3 0

Since you got the answer Me wondering why Johnny bought 500 bananas and wants to find the line on a graph with no information when the problem is 500 x 2

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On a town map, each unit of the coordinate plane represents 1 mile. Three branches of a bank are located at A(−3, 1), B(3, 3), a

Andrei [34K]

Answer:

The minimum total distance the employee may have driven before getting stuck in traffic is 8.3 miles

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of the distance between to points $(x_{1},y_{1})$

and $(x_{2},y_{2})$ i s $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

- So at first we will find the distance between the three points

∵ A = (-3 , 1) , B = (3 , 3) , C = (3 , -1)

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∴ $AB=\sqrt{(3--3)^{2}+(3-1)^{2}}=\sqrt{36+4}=\sqrt{40}=6.325$

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∵ Each unit coordinate plane represents 1 mile

∵ AB = 6.3 units

∴ The distance between branches A and B = 6.325 miles

∵ BC = 4 units

∴ The distance between branches B and C = 4 miles

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∴ The distance between branches A and C = 6.325 miles

- A bank employee drives from Branch A to Branch B and then

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∵ The distance from branch A to branch B is 6.325 miles

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∵ The half way from branch B to branch C = 1/2 × 4 = 2 miles

∴ The distance the employee may have driven before getting

stuck in traffic = 6.325 + 2 = 8.325 miles

∴ The minimum total distance the employee may have driven

before getting stuck in traffic is 8.3 miles

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3 years ago

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