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Sidana [21]
3 years ago
6

A jar contains 7 blue marbles and 2 red marbles. Suppose you choose a marble at​ random, and do not replace it. Then you choose

a second marble. Find the probability of the following event. Both of the selected marbles are red.
Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

Step-by-step explanation:

soo you start with  2 /9    as the possibility of a red marble

but you pick a red one so now there is only 1/8 chance left of a red one

soooo

2/9*1/8 = 3 / 72nds  or 1/24 th    :/  long odds....  bet a lot, if you get two reds you'll win a million :D  

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Given right triangle ABC, with altitude CD intersecting AB at point D. If AD = 5 and DB = 8, find the length of CD, in simplest
galben [10]

First we dra a triangle:

To prove that the triangles are similar we have to do the following:

Considet triangles ABC and ACD, in this case we notice that angles ACB and ADC are equal to 90°, hence they are congruent. Furthermore angles CAD and CAB are also congruent, this means that the remaining angle in both triangles will also be congruent, therefore by the AA postulate for similarity we conclude that:

\Delta ABC\approx\Delta ACD

Now consider triangles ABC and BCD, in this case we notice that angles ACB and BDC are congruent since they are both equal to 90°. Furthermore angles ABC and DBC are also congruent, this means that the remaining angle in both triangles will, once again, be congruent. Hence by the AA postulate we conclude that:

\Delta ABC\approx\Delta BCD

With this we conclude that traingles BCD and ACD are both similar to triangle ABC, and by the transitivity property of similarity we conclude that:

\Delta ACD\approx BCD

Now that we know that both triangles are similar we can use the following proportion:

\frac{h}{x}=\frac{y}{h}

this comes from the fact that the ratios should be the same in similar triangles.

From this equation we can find h:

\begin{gathered} \frac{h}{x}=\frac{y}{h} \\ h^2=xy \\ h=\sqrt[]{xy} \end{gathered}

Plugging the values we have for x and y we have that h (that is the segment CD) has length:

\begin{gathered} h=\sqrt[]{8\cdot5} \\ =\sqrt[]{40} \\ =\sqrt[]{4\cdot10} \\ =2\sqrt[]{10} \end{gathered}

Therefore, the length of segment CD is:

CD=2\sqrt[]{10}

6 0
2 years ago
S=2(lw+lh+wh) solve for w
wolverine [178]

we have

s=2(lw+lh+wh)

Solve for w means that clear variable w

s=2(lw+lh+wh)\\s=2lw+2lh+2wh

Group terms that contain the variable w, and move the other terms to the opposite side of the equation

(s-2lh)=(2lw+2wh)

Factor the variable w

(s-2lh)=w(2l+2h)

Divide both sides by (2l+2h)

(s-2lh)/(2l+2h)=w(2l+2h)/(2l+2h)

w=(s-2lh)/(2l+2h)

therefore

<u>the answer is</u>

w=(s-2lh)/(2l+2h)


7 0
3 years ago
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igomit [66]

Answer:

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Step-by-step explanation:

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