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Sidana [21]
2 years ago
6

A jar contains 7 blue marbles and 2 red marbles. Suppose you choose a marble at​ random, and do not replace it. Then you choose

a second marble. Find the probability of the following event. Both of the selected marbles are red.
Mathematics
1 answer:
Fiesta28 [93]2 years ago
3 0

Answer:

Step-by-step explanation:

soo you start with  2 /9    as the possibility of a red marble

but you pick a red one so now there is only 1/8 chance left of a red one

soooo

2/9*1/8 = 3 / 72nds  or 1/24 th    :/  long odds....  bet a lot, if you get two reds you'll win a million :D  

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move -20 to the other side

sign changes from -20 to +20

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12x= -44+20

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divide both sides by 12

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</span>
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