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joja [24]
3 years ago
7

Write an inequality for the situation. all real numbers y that are less than 4 or greater than 9

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0
Idgddavadhafhafh harharh that
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Coach leonardo used 9 1/2 meters of string to mark a soccer field for a game. He also used 2 2/5 meters of string to mark a spot
allsm [11]

Answer:

10 19/10 meters

Step-by-step explanation:

Step one:

given data

let the amount of string used for the soccer field be x

and the amount used for coach spot be y

Also, let the total string used be represented as T

Step two:

Hence the expression for the total is

T= x+y

T= 9 1/2+ 2 2/5

T= 9.5+ 2.4

T= 11.9

or

T= 119/10 meters

or

T= 10 19/10 meters

7 0
3 years ago
How do you convert 12 over 100 to a percentage ​
vova2212 [387]

Answer:

12%

Step-by-step explanation:

A percent is any fraction with 100 as a denominator. So \frac{12}{100} is the same as 12% and 4 over 100 is the same as 4%

Here's an easy was to remember, there are 100 pennies to make a dollar that like per-CENT it's out of 100.

Hope that helps and have a great day!

3 0
3 years ago
Read 2 more answers
What's the difference quotient: <br> F(x)=x^3
zaharov [31]
\dfrac{F(x+h)-F(x)}h=\dfrac{(x+h)^3-x^3}h=\dfrac{x^3+3x^2h+3xh^2+h^3-x^3}h=3x^2+3xh
5 0
3 years ago
Find all the points, if any, where the graph of 12x-5y=0 intersects (x+12)^2+(y-5)^2=169.
WITCHER [35]
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169

with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0

insert into I:
12x=0
x=0

-> only intersection is at (0,0) = option B
6 0
3 years ago
Read 2 more answers
Please help with a, b, and c!!
padilas [110]
(a). 
The product of two binomials is sometimes called FOIL.
It stands for ...

       the product of the First terms                (3j  x  3j)
plus
       the product of the Outside terms          (3j  x  5)
plus
       the product of the Inside terms            (-5  x  3j)
plus
       the product of the Last terms                (-5  x  5)

FOIL works for multiplying ANY two binomials (quantities with 2 terms).

Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .

Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.

Whenever you have     

              (the sum of two things) x (the difference of the same things)

the product is going to be

                 (the first thing)²  minus  (the second thing)² .

So in (a), that'll be      (3j)² - (5)²  =  9j² - 25 .

You could find the product with FOIL, or with this easier tool.
______________________________

(b).
This is the square of a binomial ... multiplying it by itself.  So it's
another product of 2 binomials, that both happen to be the same:

                            (4h + 5) x (4h + 5)  .

You can do the product with FOIL, or use another little tool:

The square of a binomial        (4h + 5)²    is ...

         the square of the first term               (4h)²
plus
         the square of the last term                (5)²
plus
         double the product of the terms      2 · (4h · 5)
________________________________

(c).
Use the tool I gave you in part-a . . . twice .

The product of the first 2 binomials is           (g² - 4) .

The product of the last 2 binomials is also    (g² - 4) .

Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .

5 0
3 years ago
Read 2 more answers
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