What is the common ratio of the geometric sequence below? 10, 15, 22.5, 33.75
2 answers:
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Answer: Choice D
b greater-than 3 and StartFraction 2 over 15 EndFraction
In other words,
b > 3 & 2/15
or
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Explanation:
Let's convert the mixed number 2 & 3/5 into an improper fraction.
We'll use the rule
a & b/c = (a*c + b)/c
In this case, a = 2, b = 3, c = 5
So,
a & b/c = (a*c + b)/c
2 & 3/5 = (2*5 + 3)/5
2 & 3/5 = (10 + 3)/5
2 & 3/5 = 13/5
The inequality is the same as
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Let's multiply both sides by 15 to clear out the fractions
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Now isolate the variable b
Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how
47/15 = 3 remainder 2
The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.
Answer:
- g(20) > f(20)
- g(x) exceeds f(x) for any x > 4
Step-by-step explanation:
As with most graphing problems not involving straight lines, it works well to start with a table of values. Pick a few values of x and compute f(x) and g(x) for those values. Plot the points and draw a smooth curve through them.
As in the attached, your table will show that there are two points of intersection between f(x) and g(x), and that for values of x more than 4, g(x) becomes much greater very quickly. Both curves rapidly reach the top of your graph space.
To find whether f(20) or g(20) is greater, you can evaluate the functions for that value of x.
f(20) = 20² = 400
g(20) = 2²⁰ = 1,048,576
Clearly, g(20) has a greater value.
The domain and the range of the function are all possible values of the x and y, respectively, that function can take.
The range is given by:
The domain is given by:
The range is given by:
The domain is given by: