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olasank [31]
3 years ago
6

What is the common ratio of the geometric sequence below? 10, 15, 22.5, 33.75

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
7 0

hat ratio will be 15/10 = 1.5.

Check:

.. 22.5/15 = 1.5

.. 33.75/22.5 = 1.5

seraphim [82]3 years ago
5 0
That ratio will be 15/10 = 1.5.

Check:
.. 22.5/15 = 1.5
.. 33.75/22.5 = 1.5
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Is the function f(x) =(4)^x -2 an exponential function. If so, identify the base. If not, why not?
Ne4ueva [31]

Answer:

Yes.

Base: 4

Step-by-step explanation:

Since we have 4 to the power of x, we do indeed have an exponent. The -2 just signifies vertical movement down.

7 0
3 years ago
Which equation could generate the curve in the graph below?y=3x^2-2x+1
4vir4ik [10]
If you are asking what is the graph of y = 3x^2 -2x+1.

Then, the attached file would be the answer.

To check, b^2 - 4(a)(c), for each equation and use these facts:

If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.

If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.

If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots. 

7 0
3 years ago
What is the difference in the size between 1/4 and 1 1/2
masya89 [10]
1 1/2 can be rewritten as 3/2
Difference means subtraction

So we do:
3/2-1/4
To get the same denominator, we can multiply the first fraction by 2
6/4-1/4

Then we subtract the numerators and leave the denominator
So the final answer is 5/4 of 1 1/4

Hope this helps
8 0
3 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

                                              = \frac{20}{56}  = <u>0.35</u>

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

                                                = \frac{30}{56}  = <u>0.54</u>

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

                                                = \frac{6}{56}  = <u>0.11</u>

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0
3 years ago
a bottle contains 3.5liter of water. A second bottle contains 3,750 millimeters of water .how many more millimeters are in. the
svetlana [45]
Well, if you convert 3.5 liters to 3,500 milliliters, all you do from there is do

3,750 - 3,500 = 250 milliliters
8 0
3 years ago
Read 2 more answers
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