Find the area of the rhombus below.

Mathematics

1 answer:

scoray [572]3 years ago

4 0

<u>Step-by-step explanation:</u>

diagonal 1 (d1) = 5 + 5

= 10 ft

diagonal 2 (d2) = 8 + 8

= 16 ft

area of rhombus = 1/2 × d1 × d2

= 1/2 × 10 × 16

= 80 ft²

<h2>--------------------------------</h2><h2>Follow me</h2>

You might be interested in

What is the reciprocal of 5 in fraction

nadezda [96]

Answer:

The reciprocal of 5 is 1/5. Every number has a reciprocal except for 0. There is nothing you can multiply by 0 to create a product of 1, so it has no reciprocal. Reciprocals are used when dividing fractions.

Hope this helps have a good day and God bless! <3

7 0

2 years ago

What is the perimeter of the composite figure? (6 cm,4 cm,4cm,6.5cm,9.5cm)

Olegator [25]

Answer: I need points

Step-by-step explanation:

Yep. Dkjdjdndn dkjdjdndn

8 0

2 years ago

Read 2 more answers

Which line has a constant of proportionality between y and x of 1/2?

Gnesinka [82]

Answer:

It's line C.

Step-by-step explanation:

the slope of line C is 1/2 so that's the constant of proportionality

6 0

3 years ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$