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allsm [11]
4 years ago
8

Let f(x) = (x^2+3x-5)/(x^2-8x+15) What is the domain of f(x) ?

Mathematics
1 answer:
Lyrx [107]4 years ago
8 0

Answer:

So, Domain = {set of all the real numbers except 3, 5}

Interval notation = {x ∈ set of all real numbers/ x ≠3 and x ≠ 5}

Step-by-step explanation:

The given function is f(x) = \frac{x^2 + 3x - 5}{x^2 - 8x + 15}

Here we need to find the domain.

To find the domain, let's find the restricted domain.

If we set the denominator equal to zero and solve for x, we can find the restricted domain.

Here the denominator is x^2 -8x + 15 = 0

Now we can factorize and solve for x.

(x - 3)(x - 5) = 0

(x - 3) or (x - 5) = 0

x -3 = 0  and x - 5 = 0

Solving the above equations, we get

x = 3 and x = 5

The restricted domains are x = 3 and x = 5.

Now we can find the domain.

Except 3 and 5, all the real numbers can be domain of this function.

So, Domain = {set of all the real numbers except 3, 5}

= {x ∈ set of all real numbers/ x ≠3 and x ≠ 5}.

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Irene places a mirror on the ground 24ft away from the base of an oak tree. She walks backward until she can see the top of the
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First, illustrate the problem:

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3 years ago
2.5d + 7.25 = 1 + 3.75d solve for d
dimulka [17.4K]

Answer:

5

Step-by-step explanation:

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4 0
3 years ago
(Will give Brainliest/5 Stars if correct answer)
tensa zangetsu [6.8K]
Answer: Choice D) 
The angle between the two vectors is approximately 71.6 degrees

----------------------------------------------
----------------------------------------------

Work Shown: 

Each time I write the word "dot" I mean "dot product". 

|u| = length of vector u
|u| = sqrt(u dot u)
|u| = sqrt(<8,4> dot <8,4>)
|u| = sqrt(8*8 + 4*4)
|u| = sqrt(64 + 16)
|u| = sqrt(80)
|u| = sqrt(16*5)
|u| = sqrt(16)*sqrt(5)
|u| = 4*sqrt(5)

-----------------------

|v| = length of vector v
|v| = sqrt(v dot v)
|v| = sqrt(<9,-9> dot <9,-9>)
|v| = sqrt(9*9 + (-9)*(-9))
|v| = sqrt(81+81)
|v| = sqrt(2*81)
|v| = sqrt(2)*sqrt(81)
|v| = sqrt(2)*9
|v| = 9*sqrt(2)

-----------------------

u dot v = <8,4> dot <9,-9>
u dot v = 8*9 + 4*(-9)
u dot v = 72-36
u dot v = 36

-----------------------

cos(theta) = (u dot v)/(|u|*|v|)
cos(theta) = (36)/(4*sqrt(5)*9*sqrt(2))
cos(theta) = (36)/(36*sqrt(10))
cos(theta) = 1/(sqrt(10))
cos(theta) = sqrt(10)/10
theta = arccos(sqrt(10)/10)
theta = 71.56505
which rounds to 71.6 when rounding to one decimal place (nearest tenth)

That's why the approximate answer is roughly 71.6 degrees

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The common difference is 2.5 because each number is getting 2.5 added to it to get the next number.
7 0
3 years ago
Read 2 more answers
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