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Arada [10]
3 years ago
9

Anyone in 10th grade please help me because I have to pass this later at 10 pm:(

Mathematics
1 answer:
Alenkinab [10]3 years ago
6 0

18) 19m^8n^8-\left(4m^5n\right)\left(3m^3n^7\right)

=19m^8n^8-4m^5n\cdot \:3m^3n^7

=19m^8n^8-12m^8n^8

=7m^8n^8

19) \left(-5cd\right)\left(-3c^4d\right)-\left(7c^2d^2\right)\left(2c^3\right)

=5cd\cdot \:3c^4d-7c^2d^2\cdot \:2c^3

=15c^5d^2-14c^5d^2

=c^5d^2

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