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SVEN [57.7K]
3 years ago
13

Helpppppp me pleasee

Chemistry
1 answer:
lubasha [3.4K]3 years ago
3 0

Answer: I don't Know :(

Explanation::)

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Calculate how many grams would be required to prepare 600. 0 ml of 0. 150 m of naf? molar mass of naf is 41. 9 g/mo
marta [7]

Considering the definition of molarity and molar mass, the mass of NaF required is 3.771 grams.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{liters}.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3 /><h3>Mass of NaF required</h3>

In this case, you know:

  • molarity= 0.15 M= 0.15 \frac{moles}{L}
  • number of moles= ?
  • volume= 600 mL= 0.6 L

Replacing in the definition of molarity:

0.15\frac{moles}{L} =\frac{number of moles}{0.6 L}

Solving:

0.15 \frac{moles}{L} × 0.6 L= number of moles

<u><em>0.09 moles= number of moles</em></u>

The molar mass of NaF is 41. 9 g/mol. So, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 41.9 grams, 0.09 moles of the compound contains how much mass?

mass=\frac{0.09 molesx41.9 grams}{1 mole}

<u><em>mass= 3.771 grams</em></u>

Finally, the mass of NaF required is 3.771 grams.

Learn more about

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

molarity:

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#SPJ12

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Question 19-20<br> I’m not really sure, can someone help me
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3 years ago
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The function of ribosomal RNA (rRNA) is
mr Goodwill [35]

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6 0
3 years ago
Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.
evablogger [386]

Answer:

The total amount of heat needed = 72.2116  kJ

Explanation:

Given that ;

the mass of acetic acid = 120.0 g

The initial temperature T_1 = 16.7 °C  = (16.7 + 273.15 ) K = 298.85 K

The standard molar mass of acetic acid = 60.052  g/mol

Thus ; we can determine the number of moles of acetic acid;

number of moles of acetic acid = mass of acetic acid/ molar mass of acetic acid

number of moles of acetic acid = 120.0 g/ 60.052 g/mol

number of moles of acetic acid =  1.998 moles

For acetic acid:

The standard boiling point  T_2 = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K

The enthalpy of vaporization of acetic acid \Delta H_{vap} = 23.7 kJ/mol

The heat capacity of acetic acid   c = 2.043  J/g.K

The change in temperature Δ T = T_2 - T_1

Δ T = (391.25 - 289.85)K

Δ T = 101.4 K

The amount of heat needed to bring the liquid acetic acid at 16.7°C to its boiling point is ;

q = mcΔT

From our values above;

q = 120 g ×  2.043  J/g.K × 101.4 K

q = 24859.2  J

q = 24859 /1000 kJ

q = 24.859 kJ

we have earlier calculated our number of moles o f acetic acid to be 1.998 moles;

Thus;

The needed amount of heat = \Delta_{vap} *numbers \ of  \ moles

The needed amount of heat = 23.7 \ kJ/mol * 1.998 \ moles

The needed amount of heat = 47.3526 kJ

Hence;

The total amount of heat needed = 24.859 kJ + 47.3526 kJ

The total amount of heat needed = 72.2116  kJ

4 0
3 years ago
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