So all you do is put it as a number over 100, and then put that number behind the decimal. (BEWARE! If you have a value over 10 or 1000 or any other number of that sort, then it will work too. Just make sure the number's place corresponds to the value it is "over" ---> .1 is in the 10ths place, so it would be
. .245 is in the 1000ths place so it would be
)
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Answer:
Step-by-step explanation:
We have been given that in a population of exam scores, a score of x=48 corresponds to z=+1.00 and a score of x=36 corresponds to z=-0.05.
To find the values of mean and standard deviation, we will use z-score formula as:
Let us solve for x (sample score).
Upon substituting our given values, we will get two equations as:
Upon substituting equation (1) in equation (2), we will get:
Therefore, the mean of the given data would be approximately 36.57.
Upon substituting in equation (1), we will get:
Therefore, the standard deviation for the given data would be approximately 11.43.
Answer:
.36
Step-by-step explanation:
To find the decay factor
y = a(1-b)^x
b = 1-rate of decrease
= 1-64%
= 1-.64
= .36
Answer:
-114
Step-by-step explanation:
f(x) = -4x^2 +5x
Let x = 6
f(6) = -4(6)^2 +5(6)
= -4(36) +30
- 144+30
= -114
Answer:
It would be
a plus 4 divided by 7
Step-by-step explanation: