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klemol [59]
3 years ago
5

A000 1 -1-1-1-1 AAA A 1 1 1 1 1 -1 (-1)(-1

Mathematics
2 answers:
jasenka [17]3 years ago
7 0

Answer:

-12

Step-by-step explanation:

:)

cestrela7 [59]3 years ago
3 0

The answer is -12!!!

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WILL GIVE BRAILIEST IF SOME ONE HELLLPPPPSSSSS
exis [7]

Answer:

1/5 to the 18 power or

2.62144 x 10 to the -13 power.

Or just simply 5 to the -18 power

Step-by-step explanation:

8 0
3 years ago
Please need help with this two problems
Julli [10]
I think it is 3 maybe
8 0
3 years ago
Read 2 more answers
8(2n - 5) = 3(6n - 2)
joja [24]

Answer:

n=-17

Step-by-step explanation:

8(2n-5)=3(6n-2)

1) Distributive property

16x-40=18x-6

16x−40=18x−6

2) Subtract 16x16x from both sides.

-40=18x-6-16x

−40=18x−6−16x

3) Simplify 18x-6-16x18x−6−16x to 2x-62x−6.

-40=2x-6

−40=2x−6

4) Add 66 to both sides.

-40+6=2x

−40+6=2x

5) Simplify -40+6−40+6 to -34−34.

-34=2x

−34=2x

6) Divide both sides by 22.

-\frac{34}{2}=x

−

2

34

=x

7) Simplify \frac{34}{2}

2

34

to 17

−17=x

8) Switch sides.

x=−17

5 0
3 years ago
Pls help it is due today
astra-53 [7]
X < 4, not less than or equal to.

Option A is correct
8 0
3 years ago
If x+1/x= 3, then prove that m^5+1/m^5= 123
alina1380 [7]

9514 1404 393

Explanation:

We can start with the relations ...

  \displaystyle\left(x+\frac{1}{x}\right)^3=\left(x^3+\frac{1}{x^3}\right)+3\left(x+\frac{1}{x}\right)\\\\\left(x+\frac{1}{x}\right)^5=\left(x^5+\frac{1}{x^5}\right)+5\left(x^3+\frac{1}{x^3}\right)+10\left(x+\frac{1}{x}\right)\\\\\textsf{From these, we can derive ...}\\\\x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(\left(x+\frac{1}{x}\right)^3-3\left(x+\frac{1}{x}\right)\right)-10\left(x+\frac{1}{x}\right)

  \displaystyle x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(x+\frac{1}{x}\right)^3+5\left(x+\frac{1}{x}\right)\right)\\\\x^5+\frac{1}{x^5}=3^5 -5(3^3)+5(3)\\\\=((3^2-5)3^2+5)\cdot3=(4\cdot9+5)\cdot3=(41)(3)\\\\=\boxed{123}

7 0
3 years ago
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