Point form: (6,-3)
equation form: x=6, y=-3
Sin(2θ)+sin(<span>θ)=0
use double angle formula: sin(2</span>θ)=2sin(θ)cos(<span>θ).
=>
2sin(</span>θ)cos(θ)+sin(<span>θ)=0
factor out sin(</span><span>θ)
sin(</span>θ)(2cos(<span>θ)+1)=0
by the zero product property,
sin(</span>θ)=0 ...........(a) or
(2cos(<span>θ)+1)=0.....(b)
Solution to (a): </span>θ=k(π<span>)
solution to (b): </span>θ=(2k+1)(π)+/-(π<span>)/3
for k=integer
For [0,2</span>π<span>), this translates to:
{0, 2</span>π/3,π,4π/3}
<h3>Answers:</h3>
- (a) The function is increasing on the interval (0, infinity)
- (b) The function is decreasing on the interval (-infinity, 0)
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Explanation:
You should find that the derivative is entirely negative whenever x < 0. This suggests that the function f(x) is decreasing on this interval. So that takes care of part (b).
The interval x < 0 is the same as -infinity < x < 0 which then translates to the interval notation (-infinity, 0)
Similarly, you should find that the derivative is positive when x > 0. So the function is increasing on the interval (0, infinity)
Answer:
525o • (2x - 1)
Step-by-step explanation:
