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3 years ago

Somebody help plz how can i solve the following equations of 6v+3=21

Mathematics

1 answer:

IrinaK [193]3 years ago

6 0

21-3= 18 and 18 divided by 6 equals 3 so v=3

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WITCHER [35]

12a) yes, there will be two vanilla cupcakes left over after the baker makes ten more.

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3 years ago

What fraction of 3 is 2 2/5

Yuki888 [10]

Answer: 2 2/5 is 4/5 of 3

Step-by-step explanation:

We can view that as what do we multiply 3 by to get 2 2/5 and call that value x

3x = 2 2/5

x = (2 2/5)/3

Let's turn 2 2/5 into an improper fraction... 2 2/5 = 12/5

So we have

x = (12/5)/3 = (12/5)(1/3) = 4/5

Thus 2 2/5 is 4/5 of 3

Verify: 3(4/5) = 12/5 = 2 2/5

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2 years ago

A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m,

BlackZzzverrR [31]

Answer:

301.4

Step-by-step explanation:

Volume of a cylinder=pi* $r^{2}$ *h. Assuming you want 3.14 for pi, we can substitue the 4m for r, 6 for h and 3.14 for pi.

V=3.14* $4^{2}$ *6

V=301.44

Since you want to round to nearest tenths, the answer is 301.4

8 0

3 years ago

PLEASE ANSWER NUMBER 17

zzz [600]

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3 years ago

To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI

nadya68 [22]

Part 1) To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

$\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}$

in this problem we have

$\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})$

therefore

the answer Part 1) is

Law of Sines

Part 2) To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

$g^{2}=h^{2}+i^{2}-2*h*i*cos\ G$

In this problem we have

g=HI

G=angle Beta

substitute

$HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta$

$HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}$

therefore

the answer Part 2) is

Law of Cosines

3 0

3 years ago

Read 2 more answers

Somebody help plz how can i solve the following equations of 6v+3=21​

Somebody help plz how can i solve the following equations of 6v+3=21