Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
McKenzie's work is correct because on step 3 she added the A and the B correctly.
Multiplying by 10 can be thought of as just adding a 0 to the right end of a number. If you have 2 and multiply it by 10, you get 20. For 1,234, you get 12,340. If you have 98,765, you can 987,650. Same thing applies for 100, 1000, 10000, ...., and so on. It moves it over depending on the number of 0's there are in the number. If it is 100, it will move two 0's over. For example, if you multiply 45 by 100, you get 4,500. The two zeros from 100 moved to the right side of the 45 to get 4500.
Number 5 would be D i think
Answer:
Step-by-step explanation:
8x9=72 3x16=48 72+48=120
