Answer:
the second one
Step-by-step explanation:
we dont know if the sides are congruent but we do know we have one height, one lenght, and one width. we have to find the area of two of each, and thats what the second one is
Answer:
t = 4 s
Step-by-step explanation
We can infer the origin from the t⁰ term of the quadratic as being 192 feet above the ground. Initial velocity is 16 ft/s from the t¹ term, gravity is -32 ft/s² from the t² term
0 = -16t² + 16t + 192
0 = -t² + t + 12
0 = t² - t - 12
0 = (t - 4)(t + 3)
so either
t - 4 = 0
t = 4 s
or
t + 3 = 0
t = -3 s which we ignore as it occurs before the ball is released.
Answer:
2.67 inches.
Step-by-step explanation:
Assuming that we represent the size of the squares with the letter y, such that after the squares are being cut from each corner, the rectangular length of the box that is formed can now be ( 23 - 2y), the width to be (13 - 2y) and the height be (x).
The formula for a rectangular box = L × B × W
= (23 -2y)(13-2y) (y)
= (299 - 46y - 26y + 4y²)y
= 299y - 72y² + 4y³
Now for the maximum volume:
dV/dy = 0
This implies that:
299y - 72y² + 4y³ = 299 - 144y + 12y² = 0
By using the quadratic formula; we have :

where;
a = 12; b = -144 and c = 299






Since the width is 13 inches., it can't be possible for the size of the square to be cut to be 9.33
Thus, the size of the square to be cut out from each corner to obtain the maximum volume is 2.67 inches.
7 1/5th is the anwser but thats easy your just being lazy i think