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3 years ago

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A farmer needs to get three things to the other side of the river. A chicken, a wolf, and grain. The grain can't be with the chi

cken and the wolf can't be with the chicken alone. how does he get them to the other side

1 answer:

dmitriy555 [2]3 years ago

8 0

Plot twist, the farmer decided not to move

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Which table represents a linear function

AlexFokin [52]

Answer:

3rd option (top right)

Step-by-step explanation:

3rd option represents a linear equation

y = -2x-1

Answered by GAUTHMATH

6 0

3 years ago

Please help I'm stuck on this questions thanks

polet [3.4K]

So its asking for basically the percentage of the first number out of the second.

3. 25/50 = 50%
4. 125/75 = 167%
5. 32/28 = 114%
6. 7/10 = 70%

Hope this helped! :)

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3 years ago

Cheryl has $100 on her subway gift card. Each week she buys the same lunch for $10. She wants to continue using the card until t

ziro4ka [17]

Answer:

100-60=40

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

$P(X$

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

$P(X$

Take natural log on both sides.

$ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30$

Thus, the value of x is 30.

7 0

3 years ago

Need quick answers please

Olenka [21]

Answer:

A, E, F, D

Step-by-step explanation:

Done this before

5 0

2 years ago