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djyliett [7]
3 years ago
11

Pls help with algebra 1 hmk!!

Mathematics
1 answer:
Yuliya22 [10]3 years ago
3 0
The answer is B. because it’s 1 long line, it is “and”; if it were two separate lines, it would be “or”

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Shakira se presentará en la Ruta del Vino, y para ello su anuncio ha aparecido en un espectacular por la Avenida Reforma, si la
m_a_m_a [10]

Answer:

82.4 cm

Step-by-step explanation:

The computation of the height is given below:

As we know that each right triangle contains the top angle of 20 degrees

So, the right angle & the bottom corner angle equivalent to

= 180 - 90 - 20

= 70 degrees

Now the height is

tangent = opposite leg ÷ adjacent leg

tan (70°) = height ÷ 30 cm

height = 30 cm × tan (70°)

= 82.4 cm

6 0
3 years ago
I need help on this question pls!
wlad13 [49]

Answer:103

Step-by-step explanation: find the av and then add till u git a nuber u like and submit it

5 0
2 years ago
Read 2 more answers
Pls help me on this i don't know what to do ​
Katarina [22]

Answer:

\text{A. The zeroes are 8 and -4, because }y=(x-8)(x+4)

Step-by-step explanation:

x^2-4x-32=0,\\(x-8)(x+4)=0,\\\begin{cases}x-8=0, x=\boxed{8},\\x+4=0, x=\boxed{-4}\end{cases}

8 0
4 years ago
Ecuaciones cuadraticas <br> 4x²- 20x=0<br> 3x²-42=0<br> 2x²-14x=0<br> 8x²-98=0
Setler79 [48]

Im so sorry.. I did not mean to submit an answer..

And I honestly don't know how to get rid of my answer.. but I will try to help.


4x²- 20x=0 = x_{1} = -√5, x_{2} = √5


3x²-42=0 = x_{1} = -√14, x_{2} = √14


2x²-14x=0 = x_{1} = 0, x_{2} = 7


8x²-98=0 = x_{1} = -\frac{7}{2}, x_{2} = \frac{7}{2}


I hope that these are the answers that you wanted, if they are not, I am sorry, tell me and I will try to fix them.

3 0
4 years ago
Write three powers that have values greater than 120 and less than 130? Please answer. I need it right now... :(((((
olasank [31]
Consider a few powers which are close to 120 and 130:

squares:

10^2=100\\\\ 11^2=121\\\\12^2=144

cubes:

3^3=27\\\\4^3=64\\\\5^3=125\\\\6^3=216


4th powers:

3^4=81\\\\4^4=256


now clearly there is no point of checking 5th, 6th and so on powers of numbers >2.

so check powers of 2:

2^5=32, 2^6=64, 2^7=128



So we have : 

11^2=121\\\\5^3=125\\\\2^7=128
6 0
3 years ago
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