Solve the equation for the given variable x + y = z ;x

Mathematics

1 answer:

KonstantinChe [14]3 years ago

7 0

Https://www.symbolab.com/solver/algebra-calculator/x%2By%3Dz%3Bx

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Combine Like Terms $$8y+1+2y+4

natali 33 [55]

Answer:

10y + 5

Step-by-step explanation:

You need to combine the Numbers with variables, and the numbers without variables need to be combined as well. Therefore, the answer is 10y +5.

7 0

3 years ago

Step 1: Choose a point on the line, such as (2, 5).

Alenkasestr [34]

Answer:

y-3=2(x-1)

Step-by-step explanation:

So it looks like your line goes through (2,5) and (1,3) based on what you have said.

Looking at 5 to 3, that is down 2.

Locking at 2 to 1, that is left 1.

So the slope is -2/-1 =2/1=2.

Plug in the (x1,y1)=(1,3) and slope=m=2.

So using point slope form we have y-3=2(x-1).

5 0

3 years ago

What is the perimeter of this quadrilateral? (5,5) (2, 4) (4, 1) (6, 1)

lbvjy [14]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}$

$BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}$

$DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89$