All categories

3 years ago

Find the value of x. Round to the nearest tenth.

Mathematics

2 answers:

Elenna [48]3 years ago

6 0

Answer:

Step-by-step explanation:

tan x = 4/3

tan x=1.333333

divide both sides by tan

x=1.33333/tan

x=tan inverse of 1.33333

x=53.130

x=53.13 to the nearest tenth

elena55 [62]3 years ago

4 0

Using tan(x) = 4/3

X = arctan(4/3)

X = 53.1 degrees

You might be interested in

What is the simplified form of 162

SashulF [63]

Answer:

9 √ 2

Step-by-step explanation:

1. Rewrite 162 as $9^{2}$ ⋅2

2. factor 81 out of 162

$\sqrt{81 (2)}$

3. Rewrite 81 as $9^{2}$

$\sqrt{9^{2}.2 }$

4. Pull the terms from under the radical

$\sqrt[9]{2}$

I hope this helps :)

5 0

3 years ago

Solve this for fun! I already solved it, so you can give a simple answer.

Ivanshal [37]

is this 8th grade is it is it

4 0

3 years ago

Read 2 more answers

Question 3<br> the figure needs solving help

AnnyKZ [126]

Answer:

ABC = 60

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

ACD = B+ A

100 = 40 + B

Subtract 40 from each side

100-40 = 40+B -40

60 = B

ABC = 60

8 0

3 years ago

Read 2 more answers

Mrs. Wilson packed supply bags for her students to use in a science experiment. In each bag she put 3 rubber bands and 4 paper c

n200080 [17]

Answer:

Step-by-step explanation:

In each supply bag, Mrs. Wilson packed 3 rubber bands and 4 paper clips for her students.

Now, it is given that she had used 48 rubber bands.

Hence, there will be (48/3) =16 supply bags that had been used.

Now, in 16 supply bags, there will be (16×4) =64 paper clips.

Therefore, 64 paper clips that she had used. (Answer)

3 0

3 years ago

Samantha drew Triangle JKL with the coordinates (2,3), (4, 3) and (5,2). She reflected this image over the x-axis to create an i

zavuch27 [327]

Answer:

J'(2,-3), K'(4, -3) and L'(5,-2)

Step-by-step explanation:

The given triangle has vertices at J(2,3), K(4, 3) and L(5,2).

The transformation rule for a reflection in the x-axis is:

$(x,y)\to (x,-y)$

We substitute the points to obtain the coordinates of the image triangle J'K'L'

$J(2,3)\to J'(2,-3)$

$K(4,3)\to K'(4,-3)$

$L(5,2)\to L'(5,-2)$

In other words, we negate the y-coordinates of triangle JKL to obtain the coordinates of J'K'L'

See attachment for graph.

3 0

3 years ago