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2 years ago

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Suppose $2000 is invested at 9% interest compounded continuously. How long will it take for the investment to grow to $10,000? U

se the model A ( T ) = P e^rt and round to the nearest tenth of a year.
It will take approximately ____ years for the investment to grow to $10,000.
.

1 answer:

Lady bird [3.3K]2 years ago

4 0

Answer:

7

Step-by-step explanation:

sing the equation > A = Pe^rt

20000 = 10000e^0.1t > 10% = 0.1

2 = e^0.1t

log 2 = log e^0.1t > log to the base e

log 2 = 0.1t * 1 log e to the base e =1

0.6931 = 0.1t

t = 6.931

= 7 years

Hope this helps <3

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Step-by-step explanation:

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Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

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We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

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$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

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We need to find the value of P(s₃|I).

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$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

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