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a_sh-v [17]
3 years ago
10

Siska wants to buy 5 packs of chocolate , which will cost $ 3,25 each. If ahe pays with 2 sheets of $10 , how much change will s

iska receive
Mathematics
1 answer:
GarryVolchara [31]3 years ago
3 0

$3.75

Step-by-step explanation:

times 3.25 by 5 which is 16.25 then do 20 - 16.25

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Step-by-step explanation:

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4 years ago
Bus A travels according to the function y = 125 x where y Is distance traveled In miles and x is time in hours. Bus B travels ac
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In the graph below? Where's the graph?

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3 years ago
Find the greatest common factor of the following monomials monomials 44a3 4a
Anika [276]
Hey there :)

44a³ and 4a

Let us do the numbers and variables separately

44 and 4 are both multiples of each other
Therefore, the GCF is 4

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5 0
3 years ago
Bet u can’t solve this
S_A_V [24]

Answer:

Step-by-step explanation:

Assuming you're solving for p:

m=2^{-1} *2^p(2^p-1)

Let y=2^p

Now we can re-write the equation with y instead of 2^p.

m=\frac{1}{2} y(y-1)

2m=y^2-y

y^2-y-2m=0

Use the quadratic formula to get:

y = \frac{1+\sqrt{1+8m} }{2}

or

y = \frac{1-\sqrt{1+8m} }{2}

Therefore, using natural log and log rules:

2^p = \frac{1+\sqrt{1+8m} }{2}, ln(2^p)= ln(\frac{1+\sqrt{1+8m} }{2}),pln(2) = ln(\frac{1+\sqrt{1+8m} }{2}), p = \frac{ln(\frac{1+\sqrt{1+8m} }{2})}{ln(2)}

or

2^p = \frac{1-\sqrt{1+8m} }{2}, ln(2^p)= ln(\frac{1-\sqrt{1+8m} }{2}), pln(2) = ln(\frac{1-\sqrt{1+8m} }{2}), p = \frac{ln(\frac{1-\sqrt{1+8m} }{2})}{ln(2)}

If I haven't made any mistakes this should be correct!

7 0
3 years ago
What is it quick. And drop y’all Insta ask more
Tcecarenko [31]

Answer:

225 m2

Step-by-step explanation:

area= side*side

= 15x15

225 m2

4 0
3 years ago
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