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2 years ago

7

A group of friends wants to go to the amusement park. They have $469.75 to spend on parking and admission. Parking is $10.75, an

d tickets cost $38.25 per person, including tax. Which equation or tape diagram could be used to represent the context if xx represents the number of people who can go to the amusement park?

1 answer:

attashe74 [19]2 years ago

8 0

Answer:

12

Step-by-step explanation:

469.75-10.75 =

459 ÷ 38.25 =

12

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In science class, a student is measuring the temperature of a solution in science experiment. The solution

Radda [10]

Answer:

-11.8

Step-by-step explanation:

<u>Given:</u>

-3.4 to 12.4 increased (difference = 15.8)

12.4 to 20.4 decreased (difference = 8)

20.4 to 3.2 increased (difference = 17.2)

<u>To find:</u>

Final temperature.

Solution:

As we noticed, this is a pattern of increase, decrease, increase... (and so on and so forth). From this alone, we have gotten the clue that the temperature is going to decrease. But here is the thing, How far will it decrease?

Use the difference of the starting result to find the ending result.

3.2 - 15

= -11.8

Therefore, the final temperature is -11.8.

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2 years ago

(6h+2)+(-7h-8) simplify?

lawyer [7]

Answer:

-h - 6

Step-by-step explanation:

(6h + 2) + (-7h - 8) <== remove parenthesis

6h + 2 - 7h - 8 <== combine like terms

6h - 7h + 2 - 8

-h - 6

Hope this helps!

4 0

2 years ago

Which of the following is a solution to the following system of inequalities?

iren2701 [21]

Option D: $(0,3)$ is the solution to the inequalities.

Explanation:

From the given graph, we can see that the equation of the inequalities are

$y>-x+1$ and $y\leq 2 x+3$

To determine the coordinate that satisfies the inequality, let us substitute the coordinates in both of the inequalities $y>-x+1$ and $$y$

Thus, we have,

Option A: $(1,-1)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies-1>0$ is not true.

$$y\leq 2 x+3 \implies -1\leq 5$ is true.

Since, only one equation satisfies the condition, the coordinate $(1,-1)$ is not a solution.

Hence, Option A is not the correct answer.

Option B: $(-4,0)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies0>5$ is not true.

$$y\leq 2 x+3 \implies 0\leq -5$ is not true.

Since, both the equations does not satisfy the condition, the coordinate $(-4,0)$ is not a solution.

Hence, Option B is not the correct answer.

Option C: $(3,-2)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies-2>-2$ is not true.

$$y\leq 2 x+3 \implies -2\leq 9$ is true.

Since, only one equation satisfies the condition, the coordinate $(3,-2)$ is not a solution.

Hence, Option C is not the correct answer.

Option D: $(0,3)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies3>1$ is true.

$$y\leq 2 x+3 \implies 3\leq 3$ is true.

Since, both equation satisfies the condition, the coordinate $(0,3)$ is a solution.

Hence, Option D is the correct answer.

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3 years ago

Perry bought one package of strawberries for $3. How many packages of strawberries can Mei buy if she has $9?

evablogger [386]

Answer:

3 packs

Step-by-step explanation:

1 pack = $3

To see how many she could buy divide the money she has by how much each pack costs

9/3 = 3

$3 for each pack is the same as

3+3+3 = 6+3 = 9

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2 years ago

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

3 years ago

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