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VLD [36.1K]
3 years ago
13

How many solutions does the system of equations shown below have?

Mathematics
1 answer:
rjkz [21]3 years ago
4 0

Answer:

one solution with a y value of 5

Step-by-step explanation:

/| x+y-4 = 0| x-y-6 = 0

We try to solve the equation: x+y-4 = 0

x+y-4 = 0 // - x-4

y = -(x-4)

y = 4-x

We insert the solution into one of the initial equations of our system of equations

We get a system of equations:

/| x+x-6-4 = 0| y = 4-x

2*x-10 = 0 // + 10

2*x = 10 // : 2

x = 10/2

x = 5

We insert the solution into one of the initial equations of our system of equations

For y = 4-x:  

y = 4-5

y = -1

We get a system of equations:

/| y = -1| x = 5

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Year:        1984     1989     1993     1997     2001     2003

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The scatter plot of the data is attached with the x-axis representing the number of years after 1980 and the y-axis representing the percent increase <span>of donations made on behalf of a non-profit organization.

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\begin{center}&#10;\begin{tabular}{ c| c| c| c| }&#10; x & y & x^2 & xy \\ [1ex] &#10; 4 & 7.8 & 16 & 31.2 \\  &#10; 9 & 16.3 & 81 & 146.7 \\ &#10;13 & 26.2 & 169 & 340.6 \\ &#10;17 & 38.9 & 289 & 661.3 \\ &#10;21 & 49.2 & 441 & 1,033.2 \\ &#10;23 & 62.1 & 529 & 1,428.3 \\ [1ex]&#10;\Sigma x=87 & \Sigma y=200.5 & \Sigma x^2=1,525 & \Sigma xy=3,641.3  &#10;\end{tabular}&#10;\end{center}
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Recall that the equation of the regression line is given by
y=a+bx
where
a= \frac{(\Sigma y)(\Sigma x^2)-(\Sigma x)(\Sigma xy)}{n(\Sigma x^2)-(\Sigma x)^2} = \frac{200.5(1,525)-87(3,641.3)}{6(1,525)-(87)^2}  \\  \\ = \frac{305,762.5-316793.1}{9,150-7,569} = \frac{-11,030.6}{1,581} =-6.977
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b= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{n(\Sigma x^2)-(\Sigma x)^2} = \frac{6(3,641.3)-(87)(200.5)}{6(1,525)-(87)^2}  \\  \\ = \frac{21,847.8-17,443.5}{9,150-7,569} = \frac{4,404.3}{1,581} =2.7858

Thus, the equation of the regresson line is given by
y=-6.977+2.7858x

The graph of the regression line is attached.

Using the equation, we can predict the percent donated in the year 2015. Recall that 2015 is 35 years after 1980. Thus x = 35.

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