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nikklg [1K]
2 years ago
13

Common factors of 3x^2y^2,10x^3y^2,6x^2y^2z

Mathematics
1 answer:
zepelin [54]2 years ago
6 0
X2y2 is the common factor
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Let h(x) = e^(kx) + f(x),
Anestetic [448]
\bf h(x)=e^{kx}+f(x)\implies \cfrac{dh}{dx}=ke^{kx}+f'(x)
\\\\\\
\begin{cases}
x=0\\
f'(0)=-8
\end{cases} 
h'(0)=ke^{k(0)}+(-8)\implies h'(0)=k-8
3 0
3 years ago
Solve for g.
Y_Kistochka [10]

Answer:

g =6/5                           g=-5/2

Step-by-step explanation:

(5g − 6)(2g + 5) = 0

Using the zero product property

(5g − 6)  =0          (2g + 5) = 0

5g-6+6 =0+6             2g+5-5=0-5

5g =6                          2g =-5

5g/5 = 6/5                  2g/2 =-5/2

g =6/5                           g=-5/2

7 0
3 years ago
Jim is investing in the stock market. Jim is hoping to earn $2,000 in interest in order to take a trip to Mexico. Stock A earns
Vanyuwa [196]

Given:

Total amount for investment = $32000

Rate of interest for Stock A = 4%

Rate of interest for Stock B = 7%

Jim is hoping to earn $2,000 in interest.

To find:

The amount of investments in Stock A and Stock B.

Step-by-step explanation:

Let amount of investments in Stock A = $x

Amount of investments in Stock B = $y

Total amount for investment = $32000

x+y=32000        ...(i)

Rate of interests in Stock A and Stock B are 4% and 7%. Total interests is $2000.

0.04x+0.07y=2000           ...(ii)

From (i) and (ii), we get

0.04x+0.07(32000-x)=2000

0.04x+2240-0.07x=2000

-0.03x=2000-2240

-0.03x=-240

Divide both sides by -0.03.

x=\dfrac{-240}{-0.03}

x=8000

Put x=8000 in (i).

8000+y=32000  

y=32000-8000  

y=24000  

Therefore, the amount of investments in Stock A and Stock B are $8000 and $24000 respectively.

8 0
3 years ago
In a sequence the first term is 7 and the common difference is 2 what is the fifth term
Nady [450]

7, 14, 28, 56, 112.

The 5th term is 112

6 0
3 years ago
Read 2 more answers
3 tenths +4 tenths +__________tenths
algol [13]

Well four plus seven would equal seven tenths.

6 0
3 years ago
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