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3 years ago

12

Please please help please please ASAP please I'm begging you please I have 10 minutes please y'all help please any ACE that can

help please

1 answer:

Fofino [41]3 years ago

5 0

Answer:

MN

Step-by-step explanation:

ML:RQ = MN:RS = LN:QS (corr side, similar triangles)

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3 years ago

Find the surface area 11m 2m 15m

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3 years ago

Question 5. We have 5-year statistics of average amount of wheat crop (tons) harvested from 1 km2 per year, the results are as f

tino4ka555 [31]

Answer:

a) $t=\frac{524.6-550}{\frac{27.682}{\sqrt{5}}}=-2.052$

$p_v =P(t_{(4)}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

We can say that at 5% of significance the true mean is not significantly different from 550.

b) The 95% confidence interval would be given (490.184;559.016).

We are confident at 95% that the true mean is between (490.184;559.016).

Step-by-step explanation:

Part a

Data given and notation

560, 525, 496, 543, 499

The mean and sample deviation can be calculated from the following formulas:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}$

$\bar X=524.6$ represent the sample mean

$s=27.682$ represent the sample standard deviation

$n=5$ sample size

$\mu_o =550$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the population mean is equal to 550, the system of hypothesis are:

Null hypothesis: $\mu = 550$

Alternative hypothesis: $\mu \neq 550$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{524.6-550}{\frac{27.682}{\sqrt{5}}}=-2.052$

P-value

We need to calculate the degrees of freedom first given by:

$df=n-1=5-1=4$

Since is a one-side left tailed test the p value would given by:

$p_v =P(t_{(4)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

We can say that at 5% of significance the true mean is not significantly different from 550.

Part b

The confidence interval for a proportion is given by this formula

$\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}$

The degrees of freedom are 4 from part a

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$t_{\alpha/2}=2.78$

And replacing into the confidence interval formula we got:

$524.6 - 2.78 \frac{27.682}{\sqrt{5}}=490.184$

$524.6 + 2.78 \frac{27.682}{\sqrt{5}}=559.016$

And the 95% confidence interval would be given (490.184;559.016).

We are confident at 95% that the true mean is between (490.184;559.016).

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4 years ago

What is the area and what is the excretion

qaws [65]

Answer:

24 ft²

6 × 3 + (½ × 4 × 3)

Step-by-step explanation:

Split shape into a rectangle and triangle;

The rectangle is 6 by 3 ft, the area can be found by multiplying the 2 dimensions:

6 × 3 = 18

The triangle has base 4 ft, the total length of the shape (10 ft) take the 6 ft that is part of the rectangle;

The height is 3 ft;

The area us found by ½ × base × height:

½ × 4 × 3 = 6

Add this together to get the total area.

8 0

2 years ago