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2 years ago

What is the area and what is the excretion

Mathematics

1 answer:

qaws [65]2 years ago

8 0

Answer:

24 ft²

6 × 3 + (½ × 4 × 3)

Step-by-step explanation:

Split shape into a rectangle and triangle;

The rectangle is 6 by 3 ft, the area can be found by multiplying the 2 dimensions:

6 × 3 = 18

The triangle has base 4 ft, the total length of the shape (10 ft) take the 6 ft that is part of the rectangle;

The height is 3 ft;

The area us found by ½ × base × height:

½ × 4 × 3 = 6

Add this together to get the total area.

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How many regions can be found at the left side of the normal distribution curve?

vaieri [72.5K]

Answer: it’s c.3

Hopes this helps. Um... can I please have brainliest

Step-by-step explanation:

8 0

3 years ago

The image of (4, 1) under the transformation T : (x, y) → (x + 3, y + 1) is

larisa [96]

(4 + 3 , 1 + 1)
(7,2)

4 0

3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

Two lines, R and M, are represented by the following equations:

likoan [24]

Well, i'm just going to take a stab at this:

The answer out of:
> It is (18,9) ,
> It is (9, 18)
I believe both are correct as those are both plausible coordinates (although I may be wrong)

Line R: 2x + 2y = 18 (x + y = 9)
Line M: x + y = 9
There are infinite many solutions as they are the same line.

6 0

3 years ago

Line AB passes through points A (-6,6) and B(12,3). If the equation of the line is written in slope-intercept form, y=mx+b, the.

Tomtit [17]

Answer:

You wrote the question wrong...

m is not -16 it is -1/6 (that is a big difference)

y=mx+b

y=-1/6x+b

3 = -1/6(12) + b

3 = -2 + b

b=5

Step-by-step explanation:

3 0

2 years ago