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Xelga [282]
3 years ago
10

Write the addition modeled on the number line.

Mathematics
1 answer:
stiv31 [10]3 years ago
7 0
Hahahahahahahahahahahahah
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Add. 4x−3x2−2x+−3x+3x2−2x
Gemiola [76]

Answer:

Step-by-step explanation:

4x+3x=7x

-3x-2x-3x-2x=-10x

2+2=4

-3x & 4

7 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the point (-5 7) and is parallel to the line x-5y=15
mafiozo [28]

Answer:

Step-by-step explanation:

Parallel lines have same slope.

y = mx + b

Slope = m  & y-intercept = b

x - 5y = 15

   -5y = -x + 15

      y = \frac{-1}{-5}x + \frac{15}{-5}\\\\

y = \frac{1}{5}x - 3

so, slope = 1/5   ; (-5 , 7)

y -y1 = m(x -x1)

y - 7 = \frac{1}{5}(x- [-5])\\\\y - 7 =\frac{1}{5}(x + 5)\\\\y - 7 = \frac{1}{5}x+5*\frac{1}{5}\\\\y - 7 =\frac{1}{5}x+1\\\\y =\frac{1}{5}x+1+7\\\\y=\frac{1}{5}x + 8

5 0
3 years ago
Find the equation of the straight line that is parallel to 2y - x = 7 and bisects the line joining the points (3,1) and (1,-5).​
lidiya [134]

Answer:

yes that is completely correct

7 0
3 years ago
A rabbit is 60 feet from its burrow. It can run
denis23 [38]

Answer:

More than 120 feet

Step-by-step explanation: 25 50 75- 3 secs for rabbit

40 80 120- 3 seconds so atleast 120 feet or more

8 0
3 years ago
What is 5x+4y=-14, 3x+6y=6 in matrix
yarga [219]

Answer:

\left[\begin{array}{ccc}5&4\\3&6\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}-14\\6\end{array}\right] is the required matrix form.

Step-by-step explanation:

Here, the given system of equation is:

5 x + 4 y = -14,

3 x + 6 y = 6

In a system of equation, the matrix for is given as

AX = b

Here, A  = Co-efficient Matrix, X =  Variable Matrix and B = Constant Matrix

Considering the given system:

Co-efficient Matrix(A)  = \left[\begin{array}{ccc}5&4\\3&6\end{array}\right]

Variable Matrix(X) = \left[\begin{array}{ccc}x\\y\end{array}\right]

Constant Matrix(b)   =\left[\begin{array}{ccc}-14\\6\end{array}\right]

Hence, the combined matrix form  of AX = b is

\left[\begin{array}{ccc}5&4\\3&6\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]=\left[\begin{array}{ccc}-14\\6\end{array}\right]

4 0
3 years ago
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