X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
To find the x-intercept what you do is you plug in zero for Y:
0=4x-8
Then you would add 8 to the left side and x =2
bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
quick note:
the "x" must not have a negative coefficient for the standard form, though in this case it shows like so in the inappropriate choices above.
Answer:
5:4
Step-by-step explanation:
The original ratio would be 15:12 and then you can simplify by dividing both sides by 3. So the resulting ratio would be 5:4.
Answer:
no
Step-by-step explanation:
The given point does not satisfy the first equation.
y = -8(3) -3 = -27
4 ≠ -27 . . . . . the first equation is not satisfied.
(3, 4) is not a solution