Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.
We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.
Given, π = 3.14
Beaker 1:
Radius (r₁) = 2 cm
Height (h₁) = 3 cm
Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³
Beaker 2:
Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³
Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³
Answer:
Could you link the table?
Step-by-step explanation:
A)
Knights:
25n-C+1250=0
25n+1250=C
C=25n+1250
Legions:
30n+995-C=0
30n+995=C
C=30n+995
b)
fixed cost=b in y-intercept form
variable cost, dependent on n=m in y-intercept form
Knights:
fixed=1250
variable=25
Legions:
fixed=995
variable=30
c)
insert 45 into n for both formulas:
Knights:
25*45+1250=1125+1250=2375
Legions:
30*45+995=1350+995=2345
d)With 45 guests the Legion's Banquett Hall is cheaper, but due to the higher variable cost this changes with a few more people.
calculate break even point:
difference in variable cost=5 -> per person the cost difference will decrease by this much if another person joins
current price difference: 2375-2345=30
30/5=6 -> if there are 6 additional guest (total= 51) they will cost the same
if there are more than 6 additional guest (total >51) the knight's banquett will be cheaper.
Answer:
width =5.5ft
length =18
Step-by-step explanation:
w=x
L=2x+7
area=w*L
99 = x(2x+7)
2x(x+9)-11(x+9)=0
(2x-11)(x+9)=0
2x-11=0
2x=11
x=11/2
x=5.5
L=2x+7=2*5.5+7=11+7=18
