All categories

2 years ago

if vegeta and naruto were able to fuse together what would there power level be. what would there fused name be/ awnser

Mathematics

1 answer:

elena-s [515]2 years ago

3 0

Answer:

i think that their power level would be around 25,000

Step-by-step explanation:

and i think the name would be veguto

You might be interested in

A rectangle has perimeter 92 cm and length 39 cm. What is its width?

Alik [6]

The answer:
The width is 7cm

7 0

3 years ago

Read 2 more answers

A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal

GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean income = $\frac{\sum X}{n}$ = $4.70

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = $1.83

n = sample of parking meters = 10

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.262 < $t_9$ < 2.262) = 0.95 {As the critical value of t at 9 degrees of

freedom are -2.262 & 2.262 with P = 2.5%}

P(-2.262 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.262) = 0.95

P( $-2.262 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu$ < $2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }$ , $4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }$ ]

= [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error = $2.262 \times {\frac{s}{\sqrt{n} } }$

= $2.262 \times {\frac{1.83}{\sqrt{10} } }$ = 1.31

4 0

3 years ago

Which is equivalent to 80^1/4?

den301095 [7]

$80^{\frac{1}{4}} = \sqrt[4]{80} = \sqrt[4]{2*2*2*2*5} = 4 \sqrt[4]{5}$

3 0

4 years ago

Pls help! I dont have much time left :(

kaheart [24]

Answer:

Please don't cheat on your map test. These are very important for your school, I know that lots of kids dont like school but I hate to be a party pooper. You can reportthis answer since its not a answer.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Tan(θ)/sec(θ) − cos(θ)

myrzilka [38]

Sin(theta)- cos(theta)

4 0

3 years ago