What is the measure of A using the triangle abc

Mathematics

1 answer:

djyliett [7]2 years ago

5 0

Do sin(90)*13/15 which gives you 0.87 then do inverse of sin-1(0.87) which angle A = 60.45 degrees

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Find what x is? 5×3>4+8+x a good help for your brain!

MaRussiya [10]

Answer:

x = 2.25 or any number greater

Step-by-step explanation:

5x3 > 4 + 8 + x

Make them equal to each other to get x

5x3 = 4 + 8 + x

(5x)(3) = 12 + x

- x - 3 - 3 - x

4x = 9

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Let M be the set of all nxn matrices. Define a relation on won M by A B there exists an invertible matrix P such that A = P BP S

Sophie [7]

Answer:

Recall that a relation is an equivalence relation if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.

Reflexive: We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that $A=J^{-1}AJ$ . Thus, A↔A.

Symmetric: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that $A=P^{-1}BP$ . In this equality we can perform a right multiplication by $P^{-1}$ and obtain $AP^{-1} =P^{-1}B$ . Then, in the obtained equality we perform a left multiplication by P and get $PAP^{-1} =B$ . If we write $Q=P^{-1}$ and $Q^{-1} = P$ we have $B = Q^{-1}AQ$ . Thus, B↔A.

Transitive: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have $A=P^{-1}BP$ and from B↔C we have $B=Q^{-1}CQ$ . Now, if we substitute the last equality into the first one we get